asp。来自java的netpost
不知何故,正常的httpPost不会插入我发送的值
以下是html表单:
<form id="LoginForm" name="LoginForm" method="post" action="Login.aspx?__ufps=104203&ReturnUrl=%2fsyspower3%2fmobile%2fdefault.aspx&AspxAutoDetectCookieSupport=1">
<input type="hidden" name="__VIEWSTATE" value="/wEXAQUDX19QD2QPBvUTF2XiFM6IZg==">
<input type="hidden" name="__EVENTTARGET" value="">
<input type="hidden" name="__EVENTARGUMENT" value="">
<br>
<b>Username:</b><br>
<input name="ctl00$tbUsername"/><br>
<b>Password:</b><br>
<input name="ctl00$tbPwd" type="password"/><br>
<input type="checkbox" name="ctl00$chkRememberLogin" value="0" checked>Remember Me<br>
<input name="ctl00$cmdLogin" type="submit" value="Login"/>
<input name="ctl00$cmdForgetMe" type="submit" value="Forget Me"/>
</form>
这就是我在java中要做的:
HttpPost httppost2 = new HttpPost(
"www.website.com/Login.aspx?ReturnUrl=%2fsyspower3%2fmobile%2fdefault.aspx&AspxAutoDetectCookieSupport=1");
List<NameValuePair> nameValuePairs2 = new ArrayList<NameValuePair>(4);
nameValuePairs2.add(new BasicNameValuePair("ctl00$tbUsername", "username"));
nameValuePairs2
.add(new BasicNameValuePair("ctl00$tbPwd", "password"));
nameValuePairs2.add(new BasicNameValuePair("ctl00$chkRememberLogin", "0"));
nameValuePairs2.add(new BasicNameValuePair("ctl00$cmdLogin", "Login"));
nameValuePairs2.add(new BasicNameValuePair("ctl00$cmdForgetMe", "Forget Me"));
httppost2.setEntity(new UrlEncodedFormEntity(nameValuePairs2));
response = httpclient.execute(httppost2);
String responseBody4 = EntityUtils.toString(response.getEntity());
System.out.println(responseBody4);
但是形式没有改变,我的意思是输入中也没有值。。也许这不是解决问题的方法。完成表单提交的另一种方式是什么
编辑: 据我所知,我是否还必须发布u VIEWSTATE、u EEVENTTARGET、EVENTARGUMENT值 当我从wireshark检查Post值时,它们与我从应用程序发布的once相同。。。所以这有点让人困惑。我打赌这是VIEWSTATE值,我必须首先从服务中获取它,然后在发布文章时重用它
# 1 楼答案
请在
NameValuePair
对象中添加url参数(?ReturnUrl=%2fsyspower3%2fmobile%2fdefaulture.aspx&;aspxAutoDetectCookiesSupport=1”); ),还请确保指定正在使用的协议http://
或https://