如果xml文件中缺少元素,如何在java中通过jaxb解组为该元素设置默认值
问题是我想为输入中缺少的“name”元素设置一个默认值。xml文件。如何通过jaxb实现这一点?,我不想通过java模型来实现。有没有办法通过shema或jaxb获得它。 代码如下:
1。顾客xsd
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="customer">
<xs:complexType>
<xs:sequence>
<xs:element name="name" type="stringMaxSize5" minOccurs="0" default="ss"/>
<xs:element name="phone-number" type="xs:integer" minOccurs="0" default="200" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:simpleType name="stringMaxSize5">
<xs:restriction base="xs:string">
<xs:maxLength value="5"/>
</xs:restriction>
</xs:simpleType>
</xs:schema>
2。顾客型号
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"name",
"phoneNumber"
})
@XmlRootElement(name = "customer")
public class Customer {
@XmlElement(defaultValue = "ss")
protected String name;
@XmlElement(name = "phone-number", defaultValue = "200")
protected BigInteger phoneNumber;
public String getName() {
return name;
}
public void setName(String value) {
this.name = value;
}
public BigInteger getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(BigInteger value) {
this.phoneNumber = value;
}
}
3。输入xml
<customer>
</customer>
使用以下代码进行解组:
SchemaFactory sf =SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = sf.newSchema(new File("customer.xsd"));
JAXBContext jc = JAXBContext.newInstance(Customer.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
unmarshaller.setSchema(schema);
Customer customer = (Customer) unmarshaller.unmarshal(new File("input.xml"));
System.out.println(customer.getName() + " " + customer.getPhoneNumber());
通过运行此命令,我将获得名称的空值,如果我使用下面的输入。带有“name”元素的xml文件,然后我得到name字段的默认值
input.xml file:
<customer><name/></customer>
那么,如何通过jaxb为缺少的元素设置默认值呢
# 1 楼答案
原因是您的XML文档缺少元素。见JAXB guide
请尝试此输入文档