java Spring批处理管理员，无法替换占位符“批处理”。商业模式。脚本'

Question

正在尝试将Spring批处理管理员添加到现有Spring批处理项目

我已经更新了网站。具有spring批处理管理资源和spring批处理管理器的xml

我的设置：

在src/main/resources/

我已经添加了2个属性文件。1是批处理默认属性，它是一个空文件，另一个是批处理sqlserver。包含以下内容的属性：

batch.jdbc.driver=com.microsoft.sqlserver.jdbc.SQLServerDriver    batch.jdbc.url=jdbc:sqlserver://xxx.xxx.xxx:1433;DatabaseName=SpringBatch
batch.jdbc.user=user
batch.jdbc.password=password
batch.jdbc.testWhileIdle=false
batch.jdbc.validationQuery=
batch.drop.script=/org/springframework/batch/core/schema-drop-sqlserver.sql
batch.schema.script=/org/springframework/batch/core/schema-sqlserver.sql
batch.database.incrementer.class=org.springframework.jdbc.support.incrementer.SqlServerMaxValueIncrementer
batch.lob.handler.class=org.springframework.jdbc.support.lob.DefaultLobHandler
batch.business.schema.script=business-schema-sqlserver.sql
batch.database.incrementer.parent=columnIncrementerParent
batch.grid.size=2
batch.jdbc.pool.size=6
batch.verify.cursor.position=true
batch.isolationlevel=ISOLATION_SERIALIZABLE
batch.table.prefix=BATCH_
batch.data.source.init=false

在webapp/META-INF/spring/batch/override/下，我添加了数据源上下文。包含内容的xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

       <bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
              <property name="jndiName">
                     <value>java:jboss/datasources/springBatchDB</value>
              </property>
       </bean>
</beans>

这是在JBoss EAP 6.3中运行的。每次启动服务器时，都会出现以下异常：

11:58:36,116 WARN  [org.springframework.web.context.support.XmlWebApplicationContext] (ServerService Thread Pool -- 112) Exception encountered during context initialization - cancelling refresh attempt: org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'org.springframework.jdbc.datasource.init.DataSourceInitializer#0' defined in null: Could not resolve placeholder 'batch.business.schema.script' in string value "${batch.business.schema.script}"; nested exception is java.lang.IllegalArgumentException: Could not resolve placeholder 'batch.business.schema.script' in string value "${batch.business.schema.script}"
    at org.springframework.beans.factory.config.PlaceholderConfigurerSupport.doProcessProperties(PlaceholderConfigurerSupport.java:211) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.PropertyPlaceholderConfigurer.processProperties(PropertyPlaceholderConfigurer.java:223) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.PropertyResourceConfigurer.postProcessBeanFactory(PropertyResourceConfigurer.java:86) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.context.support.PostProcessorRegistrationDelegate.invokeBeanFactoryPostProcessors(PostProcessorRegistrationDelegate.java:265) [spring-context-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.context.support.PostProcessorRegistrationDelegate.invokeBeanFactoryPostProcessors(PostProcessorRegistrationDelegate.java:162) [spring-context-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:606) [spring-context-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:462) [spring-context-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:663) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:629) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:677) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:548) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:489) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:136) [spring-webmvc-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at javax.servlet.GenericServlet.init(GenericServlet.java:242) [jboss-servlet-api_3.0_spec-1.0.2.Final-redhat-1.jar:1.0.2.Final-redhat-1]
    at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1194) [jbossweb-7.4.8.Final-redhat-4.jar:7.4.8.Final-redhat-4]
    at org.apache.catalina.core.StandardWrapper.load(StandardWrapper.java:1100) [jbossweb-7.4.8.Final-redhat-4.jar:7.4.8.Final-redhat-4]
    at org.apache.catalina.core.StandardContext.loadOnStartup(StandardContext.java:3591) [jbossweb-7.4.8.Final-redhat-4.jar:7.4.8.Final-redhat-4]
    at org.apache.catalina.core.StandardContext.start(StandardContext.java:3798) [jbossweb-7.4.8.Final-redhat-4.jar:7.4.8.Final-redhat-4]
    at org.jboss.as.web.deployment.WebDeploymentService.doStart(WebDeploymentService.java:161) [jboss-as-web-7.4.0.Final-redhat-19.jar:7.4.0.Final-redhat-19]
    at org.jboss.as.web.deployment.WebDeploymentService.access$000(WebDeploymentService.java:59) [jboss-as-web-7.4.0.Final-redhat-19.jar:7.4.0.Final-redhat-19]
    at org.jboss.as.web.deployment.WebDeploymentService$1.run(WebDeploymentService.java:94) [jboss-as-web-7.4.0.Final-redhat-19.jar:7.4.0.Final-redhat-19]
    at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) [rt.jar:1.8.0_51]
    at java.util.concurrent.FutureTask.run(FutureTask.java:266) [rt.jar:1.8.0_51]
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) [rt.jar:1.8.0_51]
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) [rt.jar:1.8.0_51]
    at java.lang.Thread.run(Thread.java:745) [rt.jar:1.8.0_51]
    at org.jboss.threads.JBossThread.run(JBossThread.java:122)
Caused by: java.lang.IllegalArgumentException: Could not resolve placeholder 'batch.business.schema.script' in string value "${batch.business.schema.script}"
    at org.springframework.util.PropertyPlaceholderHelper.parseStringValue(PropertyPlaceholderHelper.java:174) [spring-core-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.util.PropertyPlaceholderHelper.replacePlaceholders(PropertyPlaceholderHelper.java:126) [spring-core-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.PropertyPlaceholderConfigurer$PlaceholderResolvingStringValueResolver.resolveStringValue(PropertyPlaceholderConfigurer.java:259) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveStringValue(BeanDefinitionVisitor.java:282) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveValue(BeanDefinitionVisitor.java:204) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitIndexedArgumentValues(BeanDefinitionVisitor.java:150) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitBeanDefinition(BeanDefinitionVisitor.java:84) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveValue(BeanDefinitionVisitor.java:169) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitPropertyValues(BeanDefinitionVisitor.java:141) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitBeanDefinition(BeanDefinitionVisitor.java:82) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveValue(BeanDefinitionVisitor.java:169) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitList(BeanDefinitionVisitor.java:228) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveValue(BeanDefinitionVisitor.java:192) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitPropertyValues(BeanDefinitionVisitor.java:141) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitBeanDefinition(BeanDefinitionVisitor.java:82) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.resolveValue(BeanDefinitionVisitor.java:169) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitPropertyValues(BeanDefinitionVisitor.java:141) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.BeanDefinitionVisitor.visitBeanDefinition(BeanDefinitionVisitor.java:82) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    at org.springframework.beans.factory.config.PlaceholderConfigurerSupport.doProcessProperties(PlaceholderConfigurerSupport.java:208) [spring-beans-4.1.3.RELEASE.jar:4.1.3.RELEASE]
    ... 26 more

我看到那批了。商业模式。脚本来自：

spring-batch-admin-manager/src/main/resources/META-INF/spring/batch/bootstrap/manager/data-source-context.xml

其中还有从批处理sqlserver加载的“${batch.schema.script}”。属性，但不是批处理。商业模式。剧本

有人知道原因或有什么建议吗？？ 谢谢

Answer 1

我也遇到了这个问题。我没有单独的覆盖data-source-context.xml，但我通过使用名为ENVIRONMENT:

-DENVIRONMENT=postgresql

在您的情况下，它将是：

-DENVIRONMENT=sqlserver

我的猜测是，spring批处理应用程序使用spring概要文件来选择要使用的数据库类型，并且需要初始标志来种子

作为参考，以下是David Syer关于此的帖子：

http://forum.spring.io/forum/spring-projects/batch/105054-spring-batch-admin-configuration-for-pointing-the-database?p=562140#post562140

对于覆盖上下文的方法，他说：

Or you can go with the override XML, as long as you put it in the right location - from the user guide "add your own versions of the same bean definitions to a Spring XML config file in META-INF/spring/batch/override" (that's in the classpath, not the war file META-INF). In that case just override the bean named "dataSource".

所以你把文件放错地方了。您需要将其移动到类路径上的目录中

Answer 2

尝试覆盖占位符属性，包括您自己的属性

假设您将属性放置在应用程序上。属性，那么它将是：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <!   Use this to set additional properties on beans at run time  >
    <bean id="placeholderProperties" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="locations">
            <list>
                <value>classpath:/org/springframework/batch/admin/bootstrap/batch.properties</value>
                <value>classpath:batch-default.properties</value>
                <value>classpath:batch-${ENVIRONMENT:hsql}.properties</value>
                <value>classpath:application.properties</value>
            </list>
        </property>
        <property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE" />
        <property name="ignoreResourceNotFound" value="true" />
        <property name="ignoreUnresolvablePlaceholders" value="false" />
        <property name="order" value="1" />
    </bean>

</beans>