java错误：二进制运算符“>=”的操作数类型不正确，否则如果（bmi<=18.5>=25.0）

Question

错误：二进制运算符“>；=”的操作数类型错误“如果体重指数（bmi<；=18.5>；=25.0）出现其他情况，”
如何解决这个问题

    int bmi;
    
    Scanner console = new Scanner(System.in);
    
    System.out.print("Measure your height and weight.")
    Systen.out.print("Then Calculate your BMI.")
    System.out,print("Enter how many score you got : ")
    bmi = console.nextINt();
    
    if (bmi <= 18.4)
    {
        System.out.println("You're under weight, you need to gain more weight!");
    }
    else if (bmi <=18.5 >=24.9)
    {
        System.out.println("You're normal, Congrats!");
    }
    else if (bmi <=25.0)
    {
        System.out.println("You're Overweight, you need to lose some weight.");
    }

Answer 1

    int bmi;

Scanner console = new Scanner(System.in);

System.out.print("Measure your height and weight.")
Systen.out.print("Then Calculate your BMI.")
System.out,print("Enter how many score you got : ")
bmi = console.nextINt();

if (bmi <= 18.4)
{
    System.out.println("You're under weight, you need to gain more weight!");
}
else if (bmi < 25)
{
    System.out.println("You're normal, Congrats!");
}
else 
{
    System.out.println("You're Overweight, you need to lose some weight.");
}

Answer 2

是否与此相同，但仍显示错误
另外，为什么将bmi作为int，为什么不将float作为与浮点值的比较呢
将console.nextInt()替换为console.nextFloat()以接受浮点输入

float bmi = console.nextFloat();
if (bmi <= 18.4)
{
    System.out.println("You're under weight, you need to gain more weight!");
}
else if (bmi >=18.5 && bmi <=24.9)
{
    System.out.println("You're normal, Congrats!");
}
else if (bmi >=25.0)
{
    System.out.println("You're Overweight, you need to lose some weight.");
}