参数不适用于ASP服务器的java HttpPost

Question

我需要创建一个带有两个参数的HttpPost请求。我同意有很多例子，但我相信我已经完成了我的研究，但仍然没有从ASP服务器得到响应。我尝试了NameValuePair，但似乎无法获得响应页面。我猜这些参数没有添加到httpPost对象中

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("https://portal.sibt.nsw.edu.au/Default.asp");

List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
nameValuePair.add(new BasicNameValuePair("userID", id.getText().toString()));
nameValuePair.add(new BasicNameValuePair("password", pword.getText().toString()));

post.setEntity(new UrlEncodedFormEntity(nameValuePair));
HttpResponse response = client.execute(post);

String responseContent = EntityUtils.toString(response.getEntity());
Log.d("response to string", responseContent);

我再次获得登录页面，此代码返回NullPointerException：

String newURL = response.getFirstHeader("Location").getValue();

我做错了什么

Answer 1

试着这样做：

private static String urlAppendParams(String url, List<NameValuePair> lNameValuePairs) {
    if (lNameValuePairs != null) {
        List<NameValuePair> llParams = new LinkedList<NameValuePair>();
        for (NameValuePair nameValuePair : lNameValuePairs) {
            llParams.add(nameValuePair);
        }

        String sParams = URLEncodedUtils.format(llParams, "UTF-8");
        if (!url.endsWith("?")) {
            url += "?";
        }
        url += sParams;
    }
    return url;
}

Answer 2

你不用。NET网页，您必须创建。NET web服务，因为只有web服务具有post和get方法。您不请求网页。网页未收到您的消息和答复

Answer 3

当您使用浏览器（https://portal.sibt.nsw.edu.au/Default.asp）到达主页时，服务器将打开会话（您可以使用网络检查器查看set cookie标头）：

Set-Cookie:ASPSESSIONIDQCCCQQCQ=HJMMOCFAFILCLNCJIMNBACIB; path=/

您可能需要在POST登录之前对此页面发出GET请求。此外，您必须在HttpClient中启用cookie跟踪。我通常使用：

HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(ClientPNames.COOKIE_POLICY, CookiePolicy.BROWSER_COMPATIBILITY);
final HttpGet get = new HttpGet("https://portal.sibt.nsw.edu.au/Default.asp");
client.execute(get); //perform an initial GET to receive the session cookie

//now do the post...
HttpPost post = new HttpPost("https://portal.sibt.nsw.edu.au/Default.asp?Summit=OK");

List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
nameValuePair.add(new BasicNameValuePair("hcUserID", id.getText().toString()));
nameValuePair.add(new BasicNameValuePair("hcPassword", pword.getText().toString()));

post.setEntity(new UrlEncodedFormEntity(nameValuePair));
HttpResponse response = client.execute(post);

//I should be logged in.... Lets get the an internal webpage
get = new HttpGet("https://portal.sibt.nsw.edu.au/std_Alert.asp");
client.execute(get);

System.out.println(new String(get.getResponseBody()));

由于我没有有效的用户/密码，因此无法尝试此解决方案

Answer 4

我猜您只是错过了url末尾的?