使用GSON解析Java中的JSON文件

Question

我试图用java中的GSON解析这个JSON文件，但遇到了一些困难

{"group": [
{
   "name": "Team1 Student2",
   "email": "ctc-t1-s2",
   "contribution": {
      "score": 16.6,
      "comment": "From 'Team1 Student2' about 'Team1 Student2'\nAnd they said, \"You'll never get it done!\""
   }
}
,{
   "name": "Team1 Student4",
   "email": "mmi-t1-s4",
   "contribution": {
      "score": 0.4,
      "comment": "From 'Team1 Student2' about 'Team1 Student4'\nAnd they said, \"You'll never get it done!\""
   }
}
,{
   "name": "Team1 Student3",
   "email": "pco-t1-s3",
   "contribution": {
      "score": 39.1,
      "comment": "From 'Team1 Student2' about 'Team1 Student3'\nAnd they said, \"You'll never get it done!\""
   }
}
,{
   "name": "Team1 Student1",
   "email": "eyr-t1-s1",
   "contribution": {
      "score": 23.9,
      "comment": "From 'Team1 Student2' about 'Team1 Student1'\nAnd they said, \"You'll never get it done!\""
   }
}],"confidential_comments": "That's all! It was \"fun\"! (said Team1 Student2)\nDon't forget: Bring your towel \\ the cake is a lie."}

现在我有三个班，其中一个是团体班：

  public class Group {
   private List<Student> group[];

   public Group(List<Student> students[]){
       this.group =  students;
    }

    public void setStudents(List<Student> students[]) {
        this.group = students;
    }

    public List<Student>[] getStudents() {
        return group;
    }

    @Override
    public String toString() {
        return "Group{" +
                "students=" + Arrays.toString(group) +
                '}';
    }
}

以及一个学生班：

public class Student {
    private String name;
    private String sfu_email;

    public Student(String name, String email){
        this.name = name;
        this.sfu_email = email;
    }


    public String getName() {
        return name;
    }

    public String getEmail(){
        return sfu_email;
    }

    public void setEmail(String email) {
        this.sfu_email = email;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String toString(){
        return getName() + " " + getName();
    }
}

在我的主函数中，当我运行它时，我最终打印了一个空对象

 Gson gson = new Gson();

        JsonParser jsonParser = new JsonParser();

        try(Reader reader = new FileReader("FILE PATH")) {
            JsonElement jsonObject = jsonParser.parse((reader));
            System.out.println(jsonObject);

            Group students = gson.fromJson(jsonObject, Group.class);
            System.out.println(students);
            Student student = gson.fromJson(jsonObject, Student.class);
            System.out.println(student);

        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

我想知道如何解析输入文件，以便将JSON字符串放入一个对象或对象列表中？很抱歉问了这么长的问题

Answer 1

我认为出现问题的地方是，在JSON中group已经是List<Student>，但您正在尝试从gson检索组对象。我认为您需要的是一个不同的对象，比如说Reader或Response，如下所示：

class Response {
    private Group group;
}

然后做一些类似的事情：

Response response = gson.fromJson(jsonObject, Response.class);
Group = response.getGroup();

请注意，要使GSON正常工作，类中的字段名需要与JSON匹配。（因此Student中的sfu_email应该按照JSON的要求读取email）

希望这有帮助

Answer 2

Group类包含List<Student>，同样不需要在group变量名的末尾添加[]

  public class Group {

    private List<Student> group;

    public void setStudents(List<Student> students) {
        this.group = students;
    }

    public List<Student> getStudents() {
        return group;
    }

    @Override
    public String toString() {
        return "Group [group=" + group + "]";
    }
}

确保类中的字段名需要与JSON匹配

public class Student {
    private String name;
    private String email; //sfu_email changed to email

    public Student(String name, String email) {
        this.name = name;
        this.email = email;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    @Override
    public String toString() {
        return "Student [name=" + name + ", email=" + email + "]";
    }

尝试上述解决方案