解压缩java中的嵌套jar文件

Question

我正在尝试解压所有jar文件和嵌套在jar文件中的jar文件。 例如，假设有一个测试。罐子和内部的测试。jar，这里有Test1。罐子 我试图做的是创建一个临时目录并解压缩它们，当它是jar文件时，递归调用

下面是我的代码和日志。我对此一无所知。 我很确定输入的是目录。我不知道如何解决这个错误。另外，我非常确定错误来自这里（Collection<File> files = FileUtils.listFiles(root, null, recursive);）

Curr directory:/Users/younghoonkwon/jar-analyzer
unzipping directory/Users/younghoonkwon/jar-analyzer/test1.jar@
Curr directory:/Users/younghoonkwon/jar-analyzer/test1.jar@
java.lang.IllegalArgumentException: Parameter 'directory' is not a directory
    at org.apache.commons.io.FileUtils.validateListFilesParameters(FileUtils.java:545)
    at org.apache.commons.io.FileUtils.listFiles(FileUtils.java:521)
    at org.apache.commons.io.FileUtils.listFiles(FileUtils.java:691)
    at org.vulnerability.checker.JarParser.unzipJars(JarParser.java:31)
    at org.vulnerability.checker.JarParser.unzipJars(JarParser.java:38)
    at org.vulnerability.checker.VulnerabilityChecker.main(VulnerabilityChecker.java:26)
[/Users/younghoonkwon/jar-analyzer/test1.jar]

我的代码：

public void unzipJars(String toFind, String currDirectory) {
    File root = new File(currDirectory);
    try {
        boolean recursive = true;
        System.out.println("Curr directory:"+root);
        Collection<File> files = FileUtils.listFiles(root, null, recursive);
        for (Iterator<File> iterator = files.iterator(); iterator.hasNext();) {
            File file = (File) iterator.next();
            if (file.getName().endsWith(toFind)) {
                if(toFind.endsWith("jar")) {
                    unzip(file.getAbsolutePath() + "@",file.getAbsolutePath());
                    System.out.println("unzipping directory"+ file.getAbsolutePath()+"@");
                    unzipJars("jar", file.getAbsolutePath()+"@");
                    this.jarList.add(file.getAbsolutePath());
                }
            }
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
}

static void unzip(String destDirPath, String zipFilePath) throws IOException {
    Runtime.getRuntime().exec("unzip "+ zipFilePath + " -d" + destDirPath);
}

Answer 1

下面的方法decompress()解压一个JAR文件和其中的所有JAR文件（递归）

  /**
   * Size of the buffer to read/write data.
   */
  private static final int BUFFER_SIZE = 16384;

  /**
   * Decompress all JAR files located in a given directory.
   *
   * @param outputDirectory Path to the directory where the decompressed JAR files are located.
   */
  public static void decompress(final String outputDirectory) {
    File files = new File(outputDirectory);
    for (File f : Objects.requireNonNull(files.listFiles())) {
      if (f.getName().endsWith(".jar")) {
        try {
          JarUtils.decompressDependencyFiles(f.getAbsolutePath());
          // delete the original dependency jar file
          org.apache.commons.io.FileUtils.forceDelete(f);
        } catch (IOException e) {
          log.warn("Problem decompressing jar file: " + f.getAbsolutePath());
        }
      }
    }
  }

  /**
   * Decompress all JAR files (recursively).
   *
   * @param zipFile The file to be decompressed.
   */
  private static void decompressDependencyFiles(String zipFile) throws IOException {
    File file = new File(zipFile);
    try (ZipFile zip = new ZipFile(file)) {
      String newPath = zipFile.substring(0, zipFile.length() - 4);
      new File(newPath).mkdir();
      Enumeration<? extends ZipEntry> zipFileEntries = zip.entries();
      // Process each entry
      while (zipFileEntries.hasMoreElements()) {
        // grab a zip file entry
        ZipEntry entry = zipFileEntries.nextElement();
        String currentEntry = entry.getName();
        File destFile = new File(newPath, currentEntry);
        File destinationParent = destFile.getParentFile();
        // create the parent directory structure if needed
        destinationParent.mkdirs();
        if (!entry.isDirectory()) {
          BufferedInputStream is = new BufferedInputStream(zip.getInputStream(entry));
          int currentByte;
          // establish buffer for writing file
          byte[] data = new byte[BUFFER_SIZE];
          // write the current file to disk
          FileOutputStream fos = new FileOutputStream(destFile);
          try (BufferedOutputStream dest = new BufferedOutputStream(fos, BUFFER_SIZE)) {
            // read and write until last byte is encountered
            while ((currentByte = is.read(data, 0, BUFFER_SIZE)) != -1) {
              dest.write(data, 0, currentByte);
            }
            dest.flush();
            is.close();
          }
        }
        if (currentEntry.endsWith(".jar")) {
          // found a zip file, try to open
          decompressDependencyFiles(destFile.getAbsolutePath());
          FileUtils.forceDelete(new File(destFile.getAbsolutePath()));
        }
      }
    }
  }

Answer 2

这个算法对我来说似乎还可以。该错误似乎是由解压缩文件不是目录（而是文件）或不存在引起的。如果解压缩文件，您的unzip()方法不会抛出任何exeption。jar失败，因为输出文件已经存在

您之前是否运行过可能导致该问题的代码。JAR或目录包含同名的不需要的输出文件

在调用FileUtils.listFiles()之前，通过File.isDirectory()或File.isFile()检查根File对象是否实际上是一个目录，并且它是否存在（或者如果它是一个文件但不是目录）