java是否在HQL查询中使用getter/setter？

Question

我想直接使用带有HQLsql语句的包装getter/setter来使用@Embedded字段

但它不起作用：

 org.hibernate.QueryException: could not resolve property: address.zip of: Customer [SELECT c FROM Customer c WHERE c.address.zip :=zip]

以下是可能的吗

@Embeddable
pulic class ZipCode {
    String country;
    String zip;
}
@Embeddable
public class Address {
    String street;
    String town;

    @Embedded
    ZipCode zipCode;

    public String getZip() {
        return zipCode().getZip();
    }

    public void setZip(String zip) {
        zipCode.setZip(zip);
    }
}

@Entity
public class Customer {
    @Embedded
    Address address;
}

String FIND_BY_ZIP = "SELECT c FROM Customer c WHERE c.address.zip :=zip";

Answer 1

您可以将访问类型更改为AccessType.PROPERTY

@Embeddable
public class Address {
    String street;
    String town;

    @Embedded
    @Access(AccessType.PROPERTY)
    ZipCode zipCode;

    public String getZipCode() {
        return zipCode().getZip();
    }

    public void setZipCode(String zip) {
        zipCode.setZip(zip);
    }
}

这样就有可能做到

String FIND_BY_ZIP = "SELECT c FROM Customer c WHERE c.address.zipCode :=zip";

默认情况下，如果在字段中放置映射注释，则属性的访问类型为AccessType.FIELD（例如，在zipCode中有@Embedded）

为了覆盖此默认行为，可以使用AccessType.PROPERTY显式标记属性，或者将@Embedded映射注释移动到getZipCode()方法