使用HTTP状态500而不是HTTP状态400的java JAXRS响应
有时JAR-RS客户端发送错误的语法请求体。服务器应该用HTTP status 400 (Bad Request)响应,但它用HTTP status 500 (Internal Server Error)响应
代码:
JAX-B模型类:
@XmlRootElement(namespace = "http://www.test.com/test")
@XmlAccessorType(value = XmlAccessType.FIELD)
public class TestModel {
@XmlElement
private String id;
}
JAX-RS资源类:
@Path("test")
public class TestResource {
@POST
@Consumes(MediaType.APPLICATION_JSON)
public void create(TestModel testModel) {
// some code
}
}
CXF配置:
<jaxrs:server address="/rest" id="test" staticSubresourceResolution="true">
<jaxrs:serviceBeans>
<ref bean="testResource" />
</jaxrs:serviceBeans>
<jaxrs:providers>
<bean class="com.fasterxml.jackson.jaxrs.json.JacksonJaxbJsonProvider" />
</jaxrs:providers>
</jaxrs:server>
示例:
请求机构:
{"id2": "test"}
id2
是错误的,所以客户端应该得到一个HTTP status 400,但它得到了HTTP status 500
服务器日志:
Caused by: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "id2" (class test.TestModel), not marked as ignorable (one known property: "id"])
at [Source: org.apache.cxf.transport.http.AbstractHTTPDestination$1@6f30793d; line: 1, column: 10] (through reference chain: test.TestModel["id2"])
at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51)
at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:839)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1045)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1352)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1330)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:264)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:125)
at com.fasterxml.jackson.databind.ObjectReader._bind(ObjectReader.java:1470)
at com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:912)
at com.fasterxml.jackson.jaxrs.base.ProviderBase.readFrom(ProviderBase.java:811)
at org.apache.cxf.jaxrs.utils.JAXRSUtils.readFromMessageBodyReader(JAXRSUtils.java:1343)
at org.apache.cxf.jaxrs.utils.JAXRSUtils.readFromMessageBody(JAXRSUtils.java:1294)
at org.apache.cxf.jaxrs.utils.JAXRSUtils.processParameter(JAXRSUtils.java:826)
at org.apache.cxf.jaxrs.utils.JAXRSUtils.processParameters(JAXRSUtils.java:789)
at org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.processRequest(JAXRSInInterceptor.java:212)
... 68 more
有没有一种方法可以配置Jackson和/或CXF为没有schema validation或bean validation的错误语法请求主体返回HTTP状态400
# 1 楼答案
问题是,没有映射到响应(通过^{} 的方式)的异常会转换为一般服务器错误响应,因为运行时不知道如何处理该异常
jackson-jaxrs-provider
模块有ExceptionMapper
来处理Jackson基异常类JsonMappingException
和JsonParseException
。映射者分别是^{