java如何在SpringMVC3.1中保存状态？

Question

我不知道它是否是“保存状态”这个词，但如果我的控制器中有此方法：

@RequestMapping(value = "/", method = RequestMethod.GET)
    public String home(Locale locale, Model model, HttpServletRequest request) {
        Date date = new Date();
        DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG, DateFormat.LONG, locale);
        String formattedDate = dateFormat.format(date);
        model.addAttribute("serverTime", formattedDate );
        model.addAttribute("email", new Email());
        model.addAttribute("imgBg", getRandomBg(request.getRemoteHost()));
        Map sexoOpts = new HashMap();
        sexoOpts.put("M", "homem");
        sexoOpts.put("F", "mulher");

        Map sexoOpts2 = new HashMap();
        sexoOpts2.put("M", "Busco por homens");
        sexoOpts2.put("F", "Busco por mulheres");

        model.addAttribute("sexoList1", sexoOpts);
        model.addAttribute("sexoList2", sexoOpts2);
        return "index";
    }

另一种方法是：

@RequestMapping(value = "/save-email", method = RequestMethod.POST)
    public String doSaveEmail(@Valid @ModelAttribute("email") Email email,BindingResult result, Model model, HttpServletRequest request){
        model.addAttribute("imgBg", getRandomBg(request.getLocalAddr()));
        Map sexoOpts = new HashMap();
        sexoOpts.put("M", "homem");
        sexoOpts.put("F", "mulher");

        Map sexoOpts2 = new HashMap();
        sexoOpts2.put("M", "Busco por homens");
        sexoOpts2.put("F", "Busco por mulheres");

        model.addAttribute("sexoList1", sexoOpts);
        model.addAttribute("sexoList2", sexoOpts2);

        if (result.hasErrors()){
            return "index";
        }
        Date date = new Date();
        email.setCreationDate(date);

        boolean saved = false;
        try{
            saved = emailBo.saveEmail(email);
        }catch(Exception e){
            e.printStackTrace();
        }
        model.addAttribute("email", new Email());
        if (saved){
            model.addAttribute("saveStatus", "ok");
        }else{
            model.addAttribute("saveStatus", "false");
        }


        return "index";
    }

我必须重新创建hashmap，以便每次都放置性感选项，因为它将再次返回到同一页面（index.jsp）？当我从家里回来保存电子邮件时，没有办法保存这个吗

Answer 1

“spring方式”是将这两个HashMap声明为实例变量，并将它们连接到应用程序上下文（DI）中——可能将映射存储在属性文件中

Answer 2

我会将Map保存为常量，这样它就存在于方法之外，但仍然可以从内部引用

public class MyController {
    private static Map sexoOpts = new HashMap();
    private static Map sexoOpts2 = new HashMap();

    static {
        sexoOpts.put("M", "homem");
        sexoOpts.put("F", "mulher");
        sexoOpts2.put("M", "Busco por homens");
        sexoOpts2.put("F", "Busco por mulheres");
    }

    @RequestMapping(value = "/", method = RequestMethod.GET)
    public String home(Locale locale, Model model, HttpServletRequest request) {
        //I have access to sexoOpts and sexoOpts2, so there is no
        //need to instantiate them in here anymore...
    }

    @RequestMapping(value = "/save-email", method = RequestMethod.POST)
    public String doSaveEmail(@Valid @ModelAttribute("email") Email email,BindingResult result, Model model, HttpServletRequest request){
        //I have access to sexoOpts and sexoOpts2, so there is no
        //need to instantiate them in here anymore...
    }
}