java从Runnable中调用新活动

Question

我在andoid中需要处理一个流：

假设我在活动1中，然后有一个API说https://status.com/key，它告诉我是需要导航到活动2还是停留在活动1本身

因此，在Activity-1中，我将HttpRequest调用放在可运行线程中，并在每秒钟之后持续ping该API以了解其响应。当我得到回答“是”时，我就导航到活动2（谷歌地图活动）

但我注意到的是，即使在导航到Activity-2之后，Activity-1中的可运行线程仍在持续运行，因此Activity-2（Google maps活动）不断以不希望的方式加载。如何停止活动1中的可运行线程：

1. Tried Thread.stop() // Not working
2. System.exit(0) //is a bad option

final Runnable r = new Runnable() {
            public void run() {
                String myUrl="https://app.herokuapp.com/users/userredirection-pickup/"+ridetrackingno;
                Log.d("URL",myUrl);
                HttpGetRequest getRequest = new HttpGetRequest();
                try{
                    String result = getRequest.execute(myUrl).get();
                    JSONArray j=new JSONArray(result);
                    JSONObject jo= j.getJSONObject(0);
                    String r=jo.getString("status");
                    if(r.equals("yes")){
                        Intent show = new Intent (getApplicationContext(), Riding.class);
                        show.putExtra("Username",username);
                        show.putExtra("Phone",phone);

                        startActivity(show);
                    }
                } catch(Exception e)
                {
                    e.printStackTrace();
                }
                handler.postDelayed(this, 2000);
            }
        };

        handler.postDelayed(r, 2000);

请帮忙。谢谢

Answer 1

试试这个。也许它会起作用

final Runnable r = new Runnable() {
            public void run() {
                String myUrl="https://app.herokuapp.com/users/userredirection-pickup/"+ridetrackingno;
                Log.d("URL",myUrl);
                HttpGetRequest getRequest = new HttpGetRequest();
                try{
                    String result = getRequest.execute(myUrl).get();
                    JSONArray j=new JSONArray(result);
                    JSONObject jo= j.getJSONObject(0);
                    String r=jo.getString("status");
                    if(r.equals("yes")){
                        try {
                             runOnUiThread(new Runnable() {

                             @Override
                             public void run() {
                                 Intent show = new Intent (getApplicationContext(), Riding.class);
                                 show.putExtra("Username",username);
                                 show.putExtra("Phone",phone);

                                 startActivity(show);
                    }
                });
                Thread.sleep(300);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

                    }
                } catch(Exception e)
                {
                    e.printStackTrace();
                }
                handler.postDelayed(this, 2000);
            }
        };

        handler.postDelayed(r, 2000);

Answer 2

我刚才说的是

if(r.equals("yes")){
    Intent show = new Intent (getApplicationContext(), Riding.class);
    show.putExtra("Username",username);
    show.putExtra("Phone",phone);

    startActivity(show);
} else {
    handler.postDelayed(this, 2000);
}