java NetworkOnMainThreadException错误

Question

运行线路时 echoSocket = new Socket(serverHostname, 10008);我的应用程序因错误而崩溃，NetworkOnMainThreadException错误

据我所见，这与尝试在UI线程上运行socket有关。那么，我如何更改我的代码（如下）使其工作

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.Socket;
import java.net.UnknownHostException;

import 安卓.support.v7.app.ActionBarActivity;
import 安卓.support.v7.app.ActionBar;
import 安卓.support.v4.app.Fragment;
import 安卓.os.Bundle;
import 安卓.view.LayoutInflater;
import 安卓.view.Menu;
import 安卓.view.MenuItem;
import 安卓.view.View;
import 安卓.view.ViewGroup;
import 安卓.widget.Button;
import 安卓.widget.EditText;
import 安卓.widget.TextView;
import 安卓.os.Build;

public class MainActivity extends ActionBarActivity  {

    Button Bgo;
    private static TextView TV1;
    EditText Text;
    String userInput;
    Socket echoSocket = null;
    PrintWriter out = null;
    BufferedReader in = null;
    String Responce = null;
    String serverHostname;
    int section = 0;
    Boolean keepgoing = true;
    Boolean g1o = true;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Bgo = (Button) findViewById(R.id.Go);
        TV1 = (TextView) findViewById(R.id.tv1);
        Text = (EditText) findViewById(R.id.Inputtext);
        onclick();
    }

    public void send() {

        // System.out.println("type the host name"); ->>updating
        // serverHostname = new String(stdIn.readLine());

        serverHostname = new String("192.168.1.105");
        System.out.println("Attemping to connect to host " + serverHostname
                + " on port 10008.");

        try {
            echoSocket = new Socket(serverHostname, 10008);
            out = new PrintWriter(echoSocket.getOutputStream(), true);
            in = new BufferedReader(new InputStreamReader(
                    echoSocket.getInputStream()));

        } catch (UnknownHostException e) {
            TV1.setText("Don't know about host: " + serverHostname);
        } catch (IOException e) {
            TV1.setText("Couldn't get I/O for " + "the connection to: "
                    + serverHostname);
        }

        TV1.setText("type VIEW-LOG for last 5 enteries (newset first) or DC to dissconect");
    }

    public void onclick() {
        Bgo.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                if (g1o = true) {
                    TV1.setText("conecting");
                    g1o = false;
                    send();
                } else {
                    userInput = Text.getText().toString();
                    try {
                        if (userInput.equals("VIEW-LOG")) {
                            out.println(userInput);
                            int i = 0;
                            while (i < 5) {

                                Responce = in.readLine();

                                System.out.println(Responce);//this will be replace once this is working
                                i++;
                            }
                        } else if (userInput.equals("DC")) {
                            keepgoing = false;
                            System.out.println("dc");
                            out.println(userInput);
                        } else {
                            out.println(userInput);

                            System.out.println(in.readLine());

                        }
                    } catch (IOException e) {

                    }

                }
            }
        });
    }

    public void Close() {

        try {
            out.close();
            in.close();
            echoSocket.close();
        } catch (IOException e) {

        }
    }
}

XML:

<LinearLayout xmlns:安卓="http://schemas.安卓.com/apk/res/安卓"
    安卓:layout_width="fill_parent"
    安卓:layout_height="fill_parent"
    安卓:orientation="vertical" >

    <TextView
        安卓:id="@+id/tv1"
        安卓:layout_width="wrap_content"
        安卓:layout_height="wrap_content"
        安卓:text="PlaceHolder"
        安卓:textAppearance="?安卓:attr/textAppearanceLarge" />

    <EditText
        安卓:id="@+id/Inputtext"
        安卓:layout_width="match_parent"
        安卓:layout_height="wrap_content"
        安卓:ems="10" >

        <requestFocus />
    </EditText>

    <Button
        安卓:id="@+id/Go"
        安卓:layout_width="wrap_content"
        安卓:layout_height="wrap_content"
        安卓:text="Go" />

</LinearLayout>

此剂量：按一个按钮即可运行send（）；连接到服务器的。再次按下时，它会将edittext中的测试发送到服务器，如果是DC，则会断开与服务器的连接，如果是VIEW-LOG，则服务器会发送5组字符串

Answer 1

当您在主线程上执行android不允许执行的某些网络操作时，会引发此异常。将send方法调用移动到非UI线程，或者最好将代码移动到AsyncTask

Answer 2

您不应该在主线程上执行任何与网络相关的操作

或者使用Handlerhttp://developer.android.com/reference/android/os/Handler.html

或

一个AsyncTask{a2}