java 400在使用RestTemplate时请求错误。用于调用API的postForObject

Question

我试图使用RestTemplate将数据发布到我的api，但发布时它返回400个错误请求异常。 我怎样才能修好它

public void postDataToApi(List<String> accountIds, String myApiUrl) {
  ObjectMapper mapper = new ObjectMapper();
  HttpHeaders headers = new HttpHeaders();
  headers.setContentType(MediaType.APPLICATION_JSON);
  String accountIdsJsonList = mapper.writeValueAsString(accountIds);
  HttpEntity<String> entity = new HttpEntity<String>(accountIdsJsonList, headers);
  RestTemplate restTemplate = new RestTemplate();
  String result = restTemplate.postForObject(myApiUrl, entity, String.class);
}

我想发布数据的Api是YahooApi

https://ads-developers.yahoo.co.jp/reference/ads-search-api/v4/BudgetOrderService/get/en/

谢谢你的阅读

Answer 1

我想您需要在地图中设置AccountID。现在，您直接将列表发布为json请求，而无需密钥。我们可以从API文档中看到

试试这个

public void postDataToApi(List<String> accountIds, String myApiUrl) {
  ObjectMapper mapper = new ObjectMapper();
  HttpHeaders headers = new HttpHeaders();
  Map<String, Object> reqBody = new HashMap<>();
  reqBody.put("accountIds", accountIds);
  headers.setContentType(MediaType.APPLICATION_JSON);
  String accountIdsJsonList = mapper.writeValueAsString(reqBody);
  HttpEntity<String> entity = new HttpEntity<String>(accountIdsJsonList, headers);
  RestTemplate restTemplate = new RestTemplate();
  String result = restTemplate.postForObject(myApiUrl, entity, String.class);
}

Answer 2

您提到的API（yahoo）只接受授权请求。因此，yahoo API只期望具有令牌（首先生成令牌并在每个请求中发送）或客户端id&；的安全请求；客户端密码（两者结合用于授权请求）