java正则表达式将数字和字符串分开

Question

我有这样的字符串：

BLAH00001

DIK-11

DIK-2

男士5

所以所有的字符串都是一种（任意字符序列）+（数字序列）

我想要这样的东西：

一,

十一,

二,

五,

为了得到这些整数值，我想将字符序列和数字序列分开，然后执行类似Integer.parseInt(number_sequence)

有什么东西可以做这项工作吗

问候

Answer 1

String[] a ={"BLAH00001","DIK-11","DIK-2","MAN5"};
 for(String g:a)
  System.out.println(Integer.valueOf(g.split("^[A-Z]+\\-?")[1]));

 /*******************************  
   Regex Explanation :
     ^  --> StartWith
    [A-Z]+ --> 1 or more UpperCase
    \\-? --> 0 or 1 hyphen   
*********************************/

Answer 2

也许您想看看Java模式和Matcher：

• http://download.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html
• http://leepoint.net/notes-java/data/strings/40regular_expressions/26pattern-matcher.html
• http://answers.yahoo.com/question/index?qid=20071106173149AA4TUON

Answer 3

 Pattern p = Pattern.compile("^[^0-9]*([0-9]+)$");
 Matcher m = p.matcher("ASDFSA123");
 if (m.matches()) {
    resultInt = Integer.parseInt(m.group(1)));
 }

Answer 4

试试这个：

public class Main {
    public static void main(String[]args) {
        String source = "BLAH00001\n" +
                "\n" +
                "DIK-11\n" +
                "\n" +
                "DIK-2\n" +
                "\n" +
                "MAN5";
        Matcher m = Pattern.compile("\\d+").matcher(source);
        while(m.find()) {
            int i = Integer.parseInt(m.group());
            System.out.println(i);
        }
    }
}

产生：

1
11
2
5