java我需要什么正则表达式来读取这个值'12，'

Question

if (thirdLastLine.matches("Tests run: ([1-9]|1[0-9]|2[0-3]),  Failures: ([1-9]|1[0-9]|2[0-3])")) {
            System.out.println("first choice");
            String[] splitedString = thirdLastLine.split("\\s");
            //  System.out.println("splitedString: " + splitedString);
            System.out.println("splitedString: " + Arrays.toString(splitedString));

        int lastIndexofArray = (splitedString.length) - 1;
        System.out.println("lastIndexOfArray: " + lastIndexofArray);

        //for the test run:
        int thirdIndexofArray = (splitedString.length) - 4;
        System.out.println("thirdIndexofArray: " + thirdIndexofArray);

        int returnedInteger = Integer.parseInt(splitedString[lastIndexofArray]);

       int returnedThirdInteger = Integer.parseInt(splitedString[thirdIndexofArray]);
        System.out.println("You failed: " + returnedInteger + " " + "test");
          System.out.println("Numbers of test:  " + returnedThirdInteger + "test");
        feedbackString = "You failed: " + returnedInteger + " " + "test";

    } else {
        System.out.println("Nothing found");

    }

thirdLastLine包含字符串：

Tests run: 12, Failures: 4

在txt文件中。故障位工作正常，但由于字符的原因，似乎无法使测试运行位工作。我无法读取“测试运行”旁边的值，因为它旁边有一个逗号，并且我的正则表达式不满足要求。有没有关于如何解决这个问题的建议

Answer 1

您可以使用以下正则表达式来匹配数字表达式 2[0-3]|1\d|\d

这将从0到23匹配

如果你把它放在所有匹配模式中，并考虑到JE SUIS CHARLIE的答案

它变成 "Tests run: (2[0-3]|1\d|\d), Failures: (2[0-3]|1\d|\d)"

Answer 2

  Pattern p = Pattern.compile("Tests run: ([1-9]|1[0-9]|2[0-3]),  Failures: ([1-9]|1[0-9]|2[0-3])");
    Matcher m = p.matcher(thirdLastLine);
    if (m.matches()) {
        String testsRun = m.group(1);
        String failedTests = m.group(2);

        int testsRunsOutput = Integer.parseInt(testsRun);
        int failedTestsOutput = Integer.parseInt(failedTests);

        System.out.println("You failed: " + failedTestsOutput + " " + "tests");
        System.out.println("Numbers of tests:  " + testsRunsOutput + "tests");
        System.out.println("Numbers of tests: " + testsRunsOutput + " " + "You failed: " + failedTestsOutput + " " + "tests");
        feedbackString = "Numbers of tests: " + testsRunsOutput + " " + "You failed: " + failedTestsOutput + " " + "tests";

    } else {
        System.out.println("Nothing found");
    }

我刚刚使用了与我的问题相同的正则表达式和@Wil Selwood的代码。 当我运行带有“Tests run:12，Failures:4”的第三行时

输出： 测试次数：12次失败：4次测试

Answer 3

第一个数字后有一个逗号：

"Tests run: ([1-9]|1[0-9]|2[0-3]),  Failures: ([1-9]|1[0-9]|2[0-3])"    
#                         here __^

在“故障”之前可能有未知数量的空格（或制表符），因此：

"Tests run:\s+([1-9]|1[0-9]|2[0-3]),\s+Failures:\s+([1-9]|1[0-9]|2[0-3])"    

Answer 4

如果我理解你的问题，我建议你用^{}得到^{}，然后用^{} syntax之类的

Pattern p = Pattern.compile("Tests run: (\\d+), Failures: (\\d+)");
String thirdLastLine = "Tests run: 12, Failures: 4";
Matcher m = p.matcher(thirdLastLine);
if (m.matches()) {
    int testCount = Integer.parseInt(m.group(1));
    int failureCount = Integer.parseInt(m.group(2));

    System.out.printf("Numbers of tests: %d tests%n", testCount);
    String feedbackString = String.format("You failed: %d tests",
            failureCount);
    System.out.println(feedbackString);
} else {
    System.out.println("Nothing found");
}

输出为

Numbers of tests: 12 tests
You failed: 4 tests

Answer 5

你需要一个模式和匹配器来让小组出来

import java.util.regex.Matcher;
import java.util.regex.Pattern;

然后，您可以检查它是否匹配并提取匹配组

Pattern p = Pattern.compile("Tests run: ([0-9]+), Failures: ([0-9]+)");
Matcher m = p.matcher(thirdLastLine);
if(m.matches()) {
   String testsRun = m.group(1);
   String failedTests = m.group(2);
   System.out.println("You failed: " + failedTests + " " + "tests");
   System.out.println("Numbers of tests:  " + testsRun + "tests");
} else {
    System.out.println("Nothing found");
}

当然，您可能希望将结果转换为整数