java JTable未填充正确的信息
我从树映射填充表,而树映射从sql数据库填充,错误是数据在表中的显示顺序。 我已经发布了一个截图给你看
这是我的sql中的图像
public class LibraryData {
private Connection con;
private Statement stmt;
private ResultSet res;
public LibraryData() {
try {
// con = DriverManager.getConnection("jdbc:mysql://;localhost:3306")
String connectionUrl = "jdbc:sqlserver://SQL-SERVER;" + "databaseName=oe323;integratedSecurity=true;";
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
con = DriverManager.getConnection(connectionUrl);
} catch (Exception ex) {
System.out.println("Erro: " + ex);
}
}
public String listAll1() {
String output = "";
try {
stmt = con.createStatement();
res = stmt.executeQuery("SELECT * FROM LibraryTable");
while (res.next()) { // there is a result
// the name field is the thrid one in the ResultSet
// Note that with ResultSet we count the fields starting from 1
output += res.getString(1) + " " + res.getString(2) + " - "
+ res.getString(3) + " " + res.getString(4) + " "
+ res.getString(5) + "\n";
System.out.println(output);
library.put("" + res.getInt(1), new Item(res.getString(2), res.getString(3), Integer.parseInt(res.getString(4))));
}
} catch (Exception e) {
System.out.println(e);
return null;
}
return output;
}
public static class Item {
Item(String n, String a, int r) {
name = n;
artist = a;
rating = r;
}
// instance variables
private String name;
private String artist;
private int rating;
private int playCount;
public String toString() {
return name + " - " + artist;
}
}
private static Map<String, Item> library = new TreeMap<String, Item>();
//
static {
}
public static String listAll() {
String output = "";
Iterator iterator = library.keySet().iterator();
while (iterator.hasNext()) {
String key = (String) iterator.next();
Item item = library.get(key);
output += key + " " + item.name + " - " + item.artist + "\n";
}
return output;
}
public static void fillTable() {
Iterator iterator = LibraryData.library.keySet().iterator();
while (iterator.hasNext()) {
String key = (String) iterator.next();
LibraryData.Item item = LibraryData.library.get(key);
DeleteSong.data = new Object[1][3];
DeleteSong.data[0][0] = key;
DeleteSong.data[0][1] = item.artist;
DeleteSong.data[0][2] = item.name;
DeleteSong.modeltable.addRow(DeleteSong.data[0]);
}
}
public static void fillTable1() {
// listAll1();
Iterator iterator = LibraryData.library.keySet().iterator();
while (iterator.hasNext()) {
String key = (String) iterator.next();
LibraryData.Item item = LibraryData.library.get(key);
CheckLibrary.data = new Object[1][4];
CheckLibrary.data[0][0] = key;
CheckLibrary.data[0][1] = item.artist;
CheckLibrary.data[0][2] = item.name;
CheckLibrary.modeltable.addRow(CheckLibrary.data[0]);
CheckLibrary.data[0][3] = item.rating;
# 1 楼答案
问题是您的键实际上是数字,您希望按数字顺序对它们进行排序,但您的
library
键是String
的,它们按字典顺序排序,例如,1、10、11、12、13、14、15、16、17、18、19、2、20(就像a、aa、ab、ac、ad、b、ba、bb、bc、)。这种顺序在屏幕截图中很明显这是因为,出于某种原因,您决定在库映射中放置时将整数键转换为字符串:
您应该使用适合所存储信息的数据类型。如果密钥是整数,请使用整数,例如:
你有一个屏幕截图显示了这一点,但没有代码。然后您添加了代码,但删除了屏幕截图。我在你的问题中添加了屏幕截图。将来,请尝试发布与您看到的问题直接相关的代码和信息