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java如何解决org。冬眠hql。阿斯特。QuerySyntaxException:异常

我想用hibernate查询从数据库中检索一个值

这是我的java代码片段

    String hql="select groupid from group_details where groupname= :groupname and clientid= :clientid";
    Query query=session.createQuery(hql);
    query.setParameter(groupname, groupname);
    query.setParameter(clientid, clientid);
    int result = (int) query.uniqueResult();
    System.out.println(result);

我有一个bean类GroupDetails,它有settergetter字段方法

我的映射文件是

群组详细信息。哈佛商学院。xml

<hibernate-mapping>
<class name="com.aurodisplay.its.beans.GroupDetails"    table="group_details">
    <id column="groupid" name="groupid" type="java.lang.Integer"></id>
    <property column="clientid" name="clientid" type="java.lang.Integer"></property>
    <property column="groupname" name="groupname" type="java.lang.String"></property>

</class>
</hibernate-mapping>

在Hibernate配置文件中,我映射了上面的文件

冬眠。cfg。xml

<mapping resource="com/aurodisplay/its/xmlFiles/groupDetails.hbm.xml"/>

我有以下错误

org.hibernate.hql.ast.QuerySyntaxException: group_details is not mapped [select groupid from group_details where groupname= :groupname and clientid= :clientid]
org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158)
org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:87)
org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:70)
org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:257)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3056)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:2945)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:688)
org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:544)
org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281)
org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229)
org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:228)
org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:160)
org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:111)
org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:77)

有人能帮我吗


共 (1) 个答案

  1. # 1 楼答案

    您的查询是HQL查询而不是SQL查询,要使用您的类名,请使用GroupDetails而不是BDD表名group_details,如下所示:

    String hql="select groupid from GroupDetails where groupname= :groupname and clientid= :clientid";

    编辑:

    我认为setParameter也有问题,第一个参数是字段类名,而不是值本身,因此请使用:

    query.setParameter("groupname", groupname);
    query.setParameter("clientid", clientid);
    

    而不是:

    query.setParameter(groupname, groupname);
    query.setParameter(clientid, clientid);
    

    希望这有帮助