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SpringJava。lang.IllegalStateException:没有可用的事务性EntityManager

项目使用Hibernate(JPA)、Spring和Maven。我的实体和DAO在一个单独的罐子中

波姆。xml:

<project ...>
    ...
    <artifactId>database</artifactId>

    <dependencies>
        <dependency>
            <groupId>org.hibernate</groupId>
            <artifactId>hibernate-entitymanager</artifactId>
            <version>3.5.4-Final</version>
        </dependency>
    </dependencies>    
</project>

道:

public class AbstractDAO<T extends BaseEntity> implements GenericDAO<T> {


    private final Class<T> persistentClass;

    private EntityManager entityManager;

    public AbstractDAO(Class<T> entityClass) {
        super();
        this.persistentClass = entityClass;
    }

    @PersistenceContext
    public void setEntityManager(EntityManager entityManager) {
        this.entityManager = entityManager;
    }


    public EntityManager getEntityManager() {
        return entityManager;
    }

    ...

    public void fooBar() {
       //Exception from this line
       Session session = getEntityManager().unwrap(Session.class);
       ...
    }

    ....

}

我有一个模块,它使用弹簧

波姆。xml:

<project ...>
...
<artifactId>api</artifactId>

<dependencies>
    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-core</artifactId>
        <version>${spring.version}</version>
    </dependency>

    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-context</artifactId>
        <version>${spring.version}</version>
    </dependency>

    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-orm</artifactId>
        <version>${spring.version}</version>
    </dependency>
    ....
</dependencies>

 ...    
</project>

AppContext。xml:

<bean id="authService" scope="singleton" class="com.test.management.AuthServiceImpl" />

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" name="EntityManagerFactory">
        <property name="persistenceUnitName" value="default"></property>
        <property name="dataSource" ref="dataSource"></property>
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="showSql" value="true" />
                <property name="generateDdl" value="true" />
                <property name="databasePlatform" value="${db.dialect}" />
            </bean>
        </property>     
    </bean>

    <!-- Values are defined in db.properties -->
    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
        <property name="driverClassName" value="${db.driver}" />
        <property name="url" value="${db.url}" />
        <property name="username" value="${db.username}" />
        <property name="password" value="${db.password}" />
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" name="TransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory"></property>
    </bean>

    <tx:annotation-driven />

    <bean id="userDAO" scope="singleton" class="com.test.database.dao.impl.UserDAOImpl">
    </bean>


    <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />

</beans> 

服务:

public class AuthServiceImpl implements AuthService {

    @Autowired
    private UserDAO userDAO;


    @Override
    public void authorization() {
        userDAO.fooBar();

    }
}

当我试图从EntityManager获取会话时,我发现以下异常:

java.lang.IllegalStateException: No transactional EntityManager available
    at org.springframework.orm.jpa.SharedEntityManagerCreator$SharedEntityManagerInvocationHandler.invoke(SharedEntityManagerCreator.java:223)
    at $Proxy121.unwrap(Unknown Source) 

共 (4) 个答案

  1. # 1 楼答案

    您必须用@Transactional注释包围该方法:

    @Transactional
    public void fooBar() {
       //Exception from this line
       Session session = getEntityManager().unwrap(Session.class);
       ...
    }
    

    并在spring的xml配置文件中使用以下声明启用spring@Transactional处理(txManager是管理器的id)

    <tx:annotation-driven transaction-manager="txManager" />
    
  2. # 2 楼答案

    在我的例子中,这是另一个问题(对于那些在@Transactional方面有问题的人):

    @Transactional工作需要动态代理才能工作。它需要一个基于接口的代理(JDK代理,在这种情况下CGLIB不起作用)。因此,创建接口并通过服务实现它,@Transactional注释将起作用

  3. # 3 楼答案

    试试这个

    entityManager=entityManager.getEntityManagerFactory().createEntityManager();
    Session session = (Session) entityManager.unwrap(Session.class);
    
  4. # 4 楼答案

    所有这些对我都不起作用,我最终发现问题在于我将方法设置为@Transactional,而我需要类设置为@Transactional