JavaSpringMVC和静态资源

1 周，5 日 Questions & Answers 19429

我是java和spring的新手。我正在尝试制作hello world应用程序，但不知道我做错了什么

以下是我的目录结构：

test_app
-pom.xml
-src
--main
---java
----com.example.web
-----IndexController.java
---webapp
----static
-----img
------example.jpg
----WEB-INF
-----web.xml
-----dispatcher-servlet.xml
-----jsp
------index.jsp

资料来源：网状物xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app PUBLIC
        "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
        "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
         id="WebApp_ID" version="2.5">

    <display-name>Movie Reminder WebApp</display-name>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>WEB-INF/dispatcher-servlet.xml</param-value>
    </context-param>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <listener>
        <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
    </listener>
</web-app>

调度器servlet。xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">

    <context:annotation-config/>
    <context:component-scan base-package="com.example.web"/>
    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.UrlBasedViewResolver">

        <property name="viewClass"
                  value="org.springframework.web.servlet.view.JstlView"/>
        <property name="prefix" value="/WEB-INF/jsp/"/>
        <property name="suffix" value=".jsp"/>
    </bean>
</beans>

索引控制器。爪哇

package com.example.web;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class IndexController {
    @RequestMapping(value = "/")
    public ModelAndView index() {
        return new ModelAndView("index");
    }
}

索引。jsp

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
    <title>Hello Spring!</title>
</head>
<body>
<img src="<c:url value="/static/img/example.jpg" />" />
</body>
</html>

当我部署我的应用程序和请求时，我得到了404的镜像请求

http://localhost:8081/  --- http 200 ok 
http://localhost:8081/static/img/example.jpg - http 404 not found

当我向DispatcherServlet添加mvc:resources时。xml

<context:annotation-config/>
<context:component-scan base-package="com.example.web"/>
<mvc:resources mapping="/static/**" location="/static/" />

并重新编译im获取404到/请求

http://localhost:8081/  --- http 404 not foundok 
http://localhost:8081/static/img/example.jpg - http 200 ok

请帮我找出我做错了什么

@Configuration @EnableWebMvc public class WebConfig extends WebMvcConfigurerAdapter { @Override public void addResourceHandlers(ResourceHandlerRegistry registry) { registry.addResourceHandler("/resources/**").addResourceLocations("/public-resources/").setCachePeriod(31556926);`enter code here` } }

共 (5) 个答案

# 1 楼答案
这是因为servlet映射。所有传入的请求都被路由到servlet。但是servlet不知道如何满足对静态资源的请求。您需要为静态资源添加映射。有几种不同的方法：
1. 使用web服务器提供的方式。不幸的是，这取决于您拥有的服务器
2. 使用可以服务于静态资源的servlet
您使用的是什么web服务器
# 2 楼答案
只需将这两行添加到dispatcher-servlet.xml
```
<mvc:resources mapping="/static/**" location="/static/" />
<mvc:default-servlet-handler />
```
以下是default-servlet-handler的文档说明：

Configures a handler for serving static resources by forwarding to the Servlet container's default Servlet. Use of this handler allows using a "/" mapping with the DispatcherServlet while still utilizing the Servlet container to serve static resources. This handler will forward all requests to the default Servlet. Therefore it is important that it remains last in the order of all other URL HandlerMappings. That will be the case if you use the "annotation-driven" element or alternatively if you are setting up your customized HandlerMapping instance be sure to set its "order" property to a value lower than that of the DefaultServletHttpRequestHandler, which is Integer.MAX_VALUE.
# 3 楼答案
我在web中配置默认servlet。xml为所有静态资产提供服务，因此只需路由请求即可到达控制器：
```
<servlet-mapping>
    <servlet-name>default</servlet-name>
    <url-pattern>/resources/*</url-pattern>
</servlet-mapping>
```

# 4 楼答案

使用这个，它将永远有效。祝你好运：）

# 5 楼答案
从Spring 3.0及更高版本开始，您需要在Spring配置中添加以下内容：
```
<mvc:resources mapping="/static/**" location="/static/" />
```
这将告诉您的DispatcherServlet如何解析静态资源。我希望这有帮助

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JavaSpringMVC和静态资源

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