scala在后续Java调用中保留会话以播放2.0的FakereRequest

Question

我正在寻找一种在Java测试中使用Play 2.0的FakereRequest时保留会话的方法，但是在基于Scala的JAR中调用方法时，我的尝试失败了

基于Scala问题Add values to Session during testing (FakeRequest, FakeApplication)中提到的拉取请求，我认为以下内容在Java中可能有效：

public Session getSession(Result result) {
  play.api.mvc.Cookies scalaCookies =
      play.api.test.Helpers.cookies(result.getWrappedResult());
  play.api.mvc.Cookie scalaSessionCookie =
      scalaCookies.get(play.api.mvc.Session.COOKIE_NAME()).get();
  scala.Option<play.api.mvc.Cookie> optionalCookie =
      scala.Option.apply(scalaSessionCookie);

  // Compiles fine, but fails with NoSuchMethodError:
  play.api.mvc.Session scalaSession =
      play.api.mvc.Session.decodeFromCookie(optionalCookie);

  return new play.mvc.Http.Session(Scala.asJava(scalaSession.data()));
}

这编译得很好，但在运行测试时，它让我：

java.lang.NoSuchMethodError: 
  play.api.mvc.Session.decodeFromCookie(Lscala/Option;)Lplay/api/mvc/Session;

作为一个十足的Scala新手，我真的不知道我是否已经接近了。Scala会话does expose (trait) that method through CookieBaker，我认为

请注意，我不一定要寻找一种方法来运行上述代码；以上只是获得会话的第一步（可能）。接下来，我可能会尝试使用类似play.api.mvc.Session.encodeAsCookie(session)的方法将其传递给后续请求。与the ZenTasks demo类似：

@Test
public void testLoginAndMore() {
  Helpers.running(Helpers.fakeApplication(Helpers.inMemoryDatabase()), 
  new Runnable() {
    public void run() {
      Map<String, String> data = new HashMap<String, String>();
      data.put("email", "guillaume@sample.com");
      data.put("password", "secret");

      Result result = 
        callAction(controllers.routes.ref.Application.authenticate(),
          fakeRequest().withFormUrlEncodedBody(data));
      assertThat(status(result)).isEqualTo(Status.SEE_OTHER);
      assertThat(redirectLocation(result)).isEqualTo("/");

      // All fine; we're logged in. Now somehow preserve the cookie. This
      // does NOT do the trick:
      Session session = getSession(result);
      // ...subsequent callAction(..)s, somehow passing the session cookie 
    }
  });
}

1。x、 Playframework Secure module: how do you “log in” to test a secured controller in a FunctionalTest?有帮助，但在2.0中情况似乎发生了变化，我从未使用过1。十,

Answer 1

使用当前版本的Play，在测试中使用会话非常容易。您可以使用cookies(Result result)静态助手方法

// Route that sets some session data to be used in subsequent requests
Result result = callAction(...);
Http.Cookie[] cookies = FluentIterable.from(cookies(result)).toArray(Http.Cookie.class);

FakeRequest request = new FakeRequest(GET, "/someRoute").withCookies(cookies);
callAction(controllers.routes.ref.Application.requestNeedingSession(), request);

Answer 2

毕竟不需要太多的魔法。以下仅保留设置cookie的HTTP头，并在下一个请求中传递该头：

Map<String, String> data = new HashMap<String, String>();
data.put("email", "guillaume@sample.com");
data.put("password", "secret");

Result result = callAction(controllers.routes.ref.Application.authenticate(),
  fakeRequest().withFormUrlEncodedBody(data));

assertThat(status(result)).isEqualTo(Status.SEE_OTHER);
assertThat(redirectLocation(result)).isEqualTo("/");
// All fine; we're logged in. Preserve the cookies:
String cookies = header(HeaderNames.SET_COOKIE, result);

// Fetch next page, passing the cookies
result = routeAndCall(fakeRequest(GET, redirectLocation(result))
  .withHeader(HeaderNames.COOKIE, cookies));

assertThat(status(result)).isEqualTo(Status.OK);
assertThat(contentAsString(result).contains("Guillaume Bort"));

（有关仅获取PLAY_SESSIONcookie并对其进行解析的一些信息，请参见本答案的the first version。不过这几乎不需要。）