java Restlet服务器设置为JSON

Question

我在laufen和seitdem上安装了一个简单的Restlet服务器和一个新的XML服务器，这是由Jaxb generiert worden sind开发的。我喜欢图书馆，我喜欢基恩·阿农（keine Ahung）的书，但我不喜欢“Anfänger”

我是波姆。xml:

   <?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>org.example</groupId>
    <artifactId>mavenexample</artifactId>
    <version>1.0-SNAPSHOT</version>


    <repositories>
        <repository>
            <id>maven-restlet</id>
            <name>Public online Restlet repository</name>
            <url>https://maven.restlet.talend.com</url>
        </repository>
    </repositories>

    <dependencies>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>javax.servlet-api</artifactId>
            <version>4.0.0</version>
        </dependency>
        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <version>8.0.24</version>
        </dependency>

        <dependency>
            <groupId>com.google.code.gson</groupId>
            <artifactId>gson</artifactId>
            <version>2.8.7</version>
        </dependency>

        <dependency>
            <groupId>org.restlet.jse</groupId>
            <artifactId>org.restlet</artifactId>
            <version>2.3.9</version>
        </dependency>

        <dependency>
            <groupId>org.restlet.jse</groupId>
            <artifactId>org.restlet.ext.jaxb</artifactId>
            <version>2.3.9</version>
        </dependency>

    </dependencies>

    <properties>
        <maven.compiler.source>11</maven.compiler.source>
        <maven.compiler.target>11</maven.compiler.target>
    </properties>

</project>

Meine服务器资源：

public interface ITeamsResource {

    @Get("json")
    Teams readTeams();
}

我的团队是克拉斯、韦尔奇·沃姆和维森德·沃德：

//
// Diese Datei wurde mit der JavaTM Architecture for XML Binding(JAXB) Reference Implementation, v2.2.8-b130911.1802 generiert 
// Siehe <a href="http://java.sun.com/xml/jaxb">http://java.sun.com/xml/jaxb</a> 
// �nderungen an dieser Datei gehen bei einer Neukompilierung des Quellschemas verloren. 
// Generiert: 2021.04.15 um 11:25:24 AM CEST 
//


package com.htlperg.model;

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;


/**
 * <p>Java-Klasse f�r anonymous complex type.
 * 
 * <p>Das folgende Schemafragment gibt den erwarteten Content an, der in dieser Klasse enthalten ist.
 * 
 * <pre>
 * &lt;complexType>
 *   &lt;complexContent>
 *     &lt;restriction base="{http://www.w3.org/2001/XMLSchema}anyType">
 *       &lt;sequence>
 *         &lt;element ref="{}team" maxOccurs="unbounded" minOccurs="0"/>
 *       &lt;/sequence>
 *     &lt;/restriction>
 *   &lt;/complexContent>
 * &lt;/complexType>
 * </pre>
 * 
 * 
 */
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "team"
})
@XmlRootElement(name = "teams")
public class Teams
    implements Serializable
{

    protected List<Team> team;

    /**
     * Gets the value of the team property.
     * 
     * <p>
     * This accessor method returns a reference to the live list,
     * not a snapshot. Therefore any modification you make to the
     * returned list will be present inside the JAXB object.
     * This is why there is not a <CODE>set</CODE> method for the team property.
     * 
     * <p>
     * For example, to add a new item, do as follows:
     * <pre>
     *    getTeam().add(newItem);
     * </pre>
     * 
     * 
     * <p>
     * Objects of the following type(s) are allowed in the list
     * {@link Team }
     * 
     * 
     */
    public List<Team> getTeam() {
        if (team == null) {
            team = new ArrayList<Team>();
        }
        return this.team;
    }

    @Override
    public String toString() {
        String s ="";

        for(Team t: team){
            s+=t+"\n";
        }

        return s;
    }
}

我没有看到邮递员的截图。这是zwar XML的缩写，但我不知道它是什么意思，因为它是一个很好的例子，也是一个很好的程序

Postman Screenshot