java调用superinterface的默认方法是否可行？

Question

假设我有两个类，A和B：

class A
{
    void method()
    {
        System.out.println("a.method");
    }
}

class B extends A
{
    @Override
    void method()
    {
        System.out.println("b.method");
    }
}

在将B实例化为b之后，我可以调用B的方法，如b.method()。我还可以使用super.method()调用A的方法。但是如果A是一个接口，该怎么办呢

interface A
{
    default void method()
    {
        System.out.println("a.method");
    }
}

class B implements A
{
    @Override
    void method()
    {
        System.out.println("b.method");
    }
}

有没有办法让B的方法调用A的方法

Answer 1

是的，你可以。使用

A.super.method();

{a1}国家

If the form is TypeName . super . [TypeArguments] Identifier, then:

It is a compile-time error if TypeName denotes neither a class nor an interface.

If TypeName denote a class, C, then the class to search is the superclass of C.

It is a compile-time error if C is not a lexically enclosing type declaration of the current class, or if C is the class Object.

Let T be the type declaration immediately enclosing the method invocation. It is a compile-time error if T is the class Object.

Otherwise, TypeName denotes the interface to be searched, I.