数组Java | TicTacToe右对角线不工作

Question

目前正在用java开发一个tic-tac-toe游戏，我有一个checkWin（）方法，可以在4种可能的获胜条件中正确地处理3种。我遇到问题的是右对角线

代码：

public boolean checkWin(String player){
    int row = 0; // Holder to count number of player spots in row
    int d1 = 0; // Holder to count number of player spots in right diag.
    int d2 = 0; // Holder to count number of player spots in left diag.
    int[] column = new int[squares[0].length]; /* Holder to count number
    of player spots in column */

    for(int i = 0; i < size; i++){
        row = 0;
        for(int j = 0; j < size; j++){
            if(null == squares[i][j]){
                continue;
            }
            if(squares[i][j].getText().equals(player)){
                row++; /* If spot at [i][j] equals player, increase row */
                column[j]++; /* If spot at [i][j] equals player, increase 
                col */
                if(i == j){ /* If spot at i is equal to j, increase left 
                    diag */
                    d1++;
                } else if ((size - 1) == i + j){ /* If spot at i + j 
                    equals board size - 1, increase right diag. */
                    d2++;
                }
            }
        }
        if(row == size){ 
            /* 
            if spots in row is equal to size (otherwise, if it fills
            the row, return win
            */
            return true;
        }
    }
    if(size == d1 || size == d2){
        /*
        if spots in either diag is equal to size, return win
        */
        return true;
    } 
    for(int i = 0; i < column.length; i++){
        if(column[i] == size){
            /*
            if column is full of the same player character, return win
            */
            return true;
        }
    }
    /*
    otherwise, return false
    */
    return false;
}

问题在于：

                else if ((size - 1) == i + j){ /* If spot at i + j 
                    equals board size - 1, increase right diag. */
                    d2++;
                }

这样设置的原因是2D阵列的工作原理，因此对于3x3板：

[00][01][02]

[10][11][12]

[20][21][22]

当i+j=size-1时，它将计算2+0，1+1，0+2都等于2，如果size=3，则为size-1，但当我运行程序并执行右对角移动时，它不会返回win的真实值

如有任何关于如何解决此问题的建议，我们将不胜感激

Answer 1

else if ((size - 1) == i + j)

^仅当其上方的if条件为false时，才会计算此值

if(i == j)

当i == 1和j == 1时，则i == j为真，因此(size - 1) == i + j不计算

TLDR：摆脱你的else