java只读取对象的第一个数组
这是我的对象数组,因为它不允许使用arraylist,这就是我知道的。我只是用了3个,这样我就可以在做大之前练习了
veco[] accountList = new veco[3];
accountList[0] = new veco(accountNumber,billCode,billDate,accountName,accountAddress,customerNumber, periodTo,periodFrom,presentReading,previousReading,previousBalance,dueTotal);
accountList[1] = new veco(accountNumber,billCode,billDate,accountName,accountAddress,customerNumber, periodTo,periodFrom,presentReading,previousReading,previousBalance,dueTotal);
accountList[2] = new veco(accountNumber,billCode,billDate,accountName,accountAddress,customerNumber, periodTo,periodFrom,presentReading,previousReading,previousBalance,dueTotal);
在这种情况下,我会查找相同的帐号。当我使用存储在accountList[0]中的accountNumber时,它将检查accountNumber。但当我使用accountNumber时,除了accountList[0],它将直接指向表示数据库中不存在帐户ID的else
System.out.print("\nEnter Account Number: ");
int b = scanner.nextInt();
for (int j = 0; j < accountList.length; j++) {
if (b == accountList[j].getAccountNumber()) {
System.out.println("Customer Account Number: " + accountList[j].getAccountNumber());
System.out.println("Customer Account Name: " + accountList[j].getAccountName());
System.out.println("Customer Account Address: " + accountList[j].getAccountAddress());
System.out.print("Customer Number: " + accountList[j].getCustomerNumber());
System.out.println("\nBilling Code\t\tBilling Date\t\tAmount Due");
for (j = 0; j < accountList.length; j++) {
if (b == accountList[j].getAccountNumber()) {
System.out.println(accountList[j].getBillCode() + "\t\t\t" + accountList[j].getBillDate() + "\t\t\t" + (df.format(accountList[j].getDueTotal())))
}
}
} else {
System.out.print("Account ID doesn't exist in the database.\n");
break;
}
}
# 1 楼答案
您可以使用迭代器模式