jackson如何在java中从数据库中检索json对象
我尝试使用jackson获取json对象,但得到如下异常:
SEVERE: Servlet.service() for servlet [JsonProcessor] in context with path [/JJS2] threw exception [Servlet execution threw an exception] with root cause
java.lang.NoSuchMethodError: com.fasterxml.jackson.core.JsonGenerator.setCurrentValue(Ljava/lang/Object;)V
以下是java代码:
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
JSONObject jsonResponse = new JSONObject();
List<Map<String, Object>> result = new ArrayList<>();// JDK7++
try {
JSONArray data = new JSONArray();
Connection con = OracleDBConnection.getConnection();
String query = "Select * from JJS";
Statement st = con.createStatement();
ResultSet rSet = st.executeQuery(query);
while (rSet.next()) {
Map<String, Object> row = new HashMap<>();
row.put("JSON_Diagram", rSet.getString("JSON_INFO"));
result.add(row);
}
} catch (Exception e) {
e.printStackTrace();
}
ObjectMapper mapper = new ObjectMapper();
try {
response.getWriter().write(mapper.writeValueAsString(result));
response.getWriter().flush();
} catch (Exception e) {
e.printStackTrace();
}
}
以下是数据库中的json示例:
{"cells":
[{"type":"basic.Rect","position":{"x":-2,"y":33},
"size":{"width":71,"height":625},"angle":0,"isInteractive":false,
"id":"a55845b6-b753-42f0-b361-f0fcd3eaa611","z":1,
"attrs":{"rect":{"fill":"#EEEEEE","stroke":"#008B8B","stroke-width":2},
".":{"magnet":false}}}
数据库只有一列包含json数据
# 1 楼答案
jackson-core
(流式传输,低级编码器/解码器)和jackson-databind
(对象映射)之间存在版本不兼容。最有可能的是jackson-databind
的2.6版本,但是jackson-core
的一些早期版本。这些组件的次要版本必须匹配;或者至少jackson-databind
次要版本不能晚于jackson-core
版本