datetime Java：使用时间单位将秒转换为天、小时、分钟和秒

Question

我使用TimeStamp类将秒转换为天、小时、分钟、秒。我使用了以下代码

public static void calculateTime(long seconds) {
        int day = (int)TimeUnit.SECONDS.toDays(seconds);        
        long hours = TimeUnit.SECONDS.toHours(seconds) - TimeUnit.SECONDS.toHours(TimeUnit.SECONDS.toDays(seconds));
        long minute = TimeUnit.SECONDS.toMinutes(seconds) - TimeUnit.SECONDS.toMinutes(TimeUnit.SECONDS.toHours(seconds));
        long second = TimeUnit.SECONDS.toSeconds(seconds) - TimeUnit.SECONDS.toSeconds(TimeUnit.SECONDS.toMinutes(seconds));

        System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);

    }

但我没有得到正确的结果。 例如，当我将此方法调用为calculateTime(3600)时，它将结果作为Day 0 Hour 1 Minute 60 Seconds 3540而不是Day 0 Hour 1 Minute 0 Seconds 0

我的逻辑怎么了？请帮帮我

Answer 1

下面是我创建的代码：（3600秒显示“天：0小时：1分钟：0秒：0”）

public class TimeConvert 
{
    public static void main(String[] args) 
    {
        int fsec,d,h,m,s,temp=0,i;
        fsec=3600;
        //For Days
        if(fsec>=86400)
        {
            temp=fsec/86400;
            d=temp;
            for(i=1;i<=temp;i++)
            {
                fsec-=86400;
            }
        }
        else
        {
            d=0;
        }
        //For Hours
        if(fsec>=3600)
        {
            temp=fsec/3600;
            h=temp;
            for(i=1;i<=temp;i++)
            {
                fsec-=3600;
            }            
        }
        else
        {
            h=0;
        }
        //For Minutes
        if(fsec>=60)
        {
            temp=fsec/60;
            m=temp;
            for(i=1;i<=temp;i++)
            {
                fsec-=60;
            }            
        }
        else
        {
            m=0;
        }
        //For Seconds
        if(fsec>=1)
        {
            s=fsec;            
        }
        else
        {
            s=0;
        }
        System.out.println("Days:"+d+" Hours:"+h+" Minutes:"+m+" Seconds:"+s);
    }
}

希望它能回答你的问题

Answer 2

试试这个

public static void calculateTime(long seconds) {

int day = (int)TimeUnit.SECONDS.toDays(seconds);        
long hours = TimeUnit.SECONDS.toHours(seconds) ;

long tempSec = seconds - (TimeUnit.HOURS.toSeconds(hours) );
System.out.println("after hours calculation "+ tempSec);

long minute = TimeUnit.SECONDS.toMinutes(tempSec); 

if(tempSec > TimeUnit.MINUTES.toSeconds(minute)){
    tempSec = tempSec - (TimeUnit.MINUTES.toSeconds(minute) );          
}else{
    tempSec = TimeUnit.MINUTES.toSeconds(minute) - tempSec;
}
System.out.println("after min calculation "+ tempSec);


long second = TimeUnit.SECONDS.toSeconds(tempSec) ;

System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}

Answer 3

您可以这样做，只使用TimeUnit：

public static void calculateTime(long seconds) {
    int day = (int) TimeUnit.SECONDS.toDays(seconds);
    long hours = TimeUnit.SECONDS.toHours(seconds) -
                 TimeUnit.DAYS.toHours(day);
    long minute = TimeUnit.SECONDS.toMinutes(seconds) - 
                  TimeUnit.DAYS.toMinutes(day) -
                  TimeUnit.HOURS.toMinutes(hours);
    long second = TimeUnit.SECONDS.toSeconds(seconds) -
                  TimeUnit.DAYS.toSeconds(day) -
                  TimeUnit.HOURS.toSeconds(hours) - 
                  TimeUnit.MINUTES.toSeconds(minute);
    System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}

或者稍微短一点，但可能不那么直观

public static void calculateTime(long seconds) {
    int day = (int) TimeUnit.SECONDS.toDays(seconds);
    long hours = TimeUnit.SECONDS.toHours(seconds) -
                 TimeUnit.DAYS.toHours(day);
    long minute = TimeUnit.SECONDS.toMinutes(seconds) -
                  TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(seconds));
    long second = TimeUnit.SECONDS.toSeconds(seconds) -
                  TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(seconds));
    System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}

Answer 4

晚了，但很有帮助

get time in the format 00:00:00

/**
     * The time in format.
     *
     * in The Format of 00:00:00
     */

public String getTimeInFormat(long _SECONDS)
{
    if(TimeUnit.SECONDS.toHours(_SECONDS)>0)
    {
        return  String.format("%02d:%02d:%02d",
                TimeUnit.SECONDS.toHours(_SECONDS),
                TimeUnit.SECONDS.toMinutes(_SECONDS) -
                        TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(_SECONDS)),
                TimeUnit.SECONDS.toSeconds(_SECONDS) -
                        TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(_SECONDS)));
    }
    else {
        return  String.format("%02d:%02d",
                TimeUnit.SECONDS.toMinutes(_SECONDS) -
                        TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(_SECONDS)),
                TimeUnit.SECONDS.toSeconds(_SECONDS) -
                        TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(_SECONDS)));
    }

}

Answer 5

应该是

 int day = (int)TimeUnit.SECONDS.toDays(seconds);        
 long hours = TimeUnit.SECONDS.toHours(seconds) - (day *24);
 long minute = TimeUnit.SECONDS.toMinutes(seconds) - (TimeUnit.SECONDS.toHours(seconds)* 60);
 long second = TimeUnit.SECONDS.toSeconds(seconds) - (TimeUnit.SECONDS.toMinutes(seconds) *60);

编辑 说明：

1. 日计算正确，无需解释
2. 时间单位。秒。toHours（秒）将为您提供从秒到小时的直接转换，而不考虑您已经计算的天数。减去你已经拥有的天数的小时数，即第24天。你现在还有剩余的时间
3. 分钟和秒都一样。你需要分别减去已经得到的小时和分钟

Answer 6

简单方法：

public static void calculateTime(long seconds) {
    long sec = seconds % 60;
    long minutes = seconds % 3600 / 60;
    long hours = seconds % 86400 / 3600;
    long days = seconds / 86400;

    System.out.println("Day " + days + " Hour " + hours + " Minute " + minutes + " Seconds " + sec);
}