java如果我的数据在数组列表中，如何从网络获取响应

Question

我想从网络上得到响应，这是一个数组列表，并将该数组列表发送到下一个活动，以便我可以在我的recyclerView中显示它

public void sendPost(){
        Call<List<SearchModel>> call = mAPIService.sendSearch("1","2");
        call.enqueue(new Callback<List<SearchModel>>() {
            @Override
            public void onResponse(Call<List<SearchModel>> call, retrofit2.Response<List<SearchModel>> response) {
                Toast.makeText(getApplicationContext(), " Responce " +response.body(), Toast.LENGTH_SHORT).show();
                if (response.isSuccessful()){

                    SearchModel searchResponse = response.body().get(0);
                    assert searchResponse != null;

                    searchModelList.add(searchResponse);
                    Intent intent1 = new Intent(getApplicationContext(),ResultsSearch.class);
                    Bundle bundle = new Bundle();
                    bundle.putSerializable("mylist",searchModelList);
                    intent1.putExtras(bundle);
                    startActivity(intent1);

                }else {
                    Toast.makeText(getApplicationContext(),"Something is error",Toast.LENGTH_SHORT).show();
                }

            }

            @Override
            public void onFailure(Call<List<SearchModel>> call, Throwable t) {
                Log.e("msg","Failed "+t);
                Toast.makeText(getApplicationContext(),t.getMessage(),Toast.LENGTH_LONG).show();
            }
        });
    }

而且，当我通过在模型中存储该值来发送单个数据时，我的应用程序崩溃。如何解决这些错误。 我将在下一个活动中获得以下值：

public class ResultsSearch extends AppCompatActivity {
    Intent mIntent;
    List vehicleResponse;
    Bundle bundle;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_results_search);

        bundle = this.getIntent().getExtras();
        init();


    }
    private void init(){

        vehicleResponse = bundle.getParcelableArrayList("mylist");

        RecyclerView recyclerView = (RecyclerView) findViewById(R.id.card_recycler_view);
        recyclerView.setHasFixedSize(true);

        RecyclerView.LayoutManager layoutManager = new LinearLayoutManager(this);
        recyclerView.setLayoutManager(layoutManager);

        SearchAdapter searchAdapter = new SearchAdapter(vehicleResponse,getApplicationContext());
        recyclerView.setAdapter(searchAdapter);


    }
}

Answer 1

确保SearchModel是可打包的。 但正确的方法是在Bundle中传递search的参数，并对ResultsSearch进行API调用