java如何在AES encryptopn中将数组大小从SHA1输出的20字节更改为适合IV 16字节
我需要实现AES-CBC加密算法,但我手动创建initialize IV的示例如下:
//initialize IV manually
byte[] ivBytes = new byte[]{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
我拥有的AES-CBC:
package xxxx;
import javax.crypto.Cipher;
import javax.crypto.KeyGenerator;
import javax.crypto.SecretKey;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
public class AES_CBC
{
public static void main(String[] args)
{
try
{
//Lookup a key generator for the AES cipher
KeyGenerator kg = KeyGenerator.getInstance("AES");
SecretKey key = kg.generateKey();
SecretKeySpec keySpec = new
SecretKeySpec(key.getEncoded(), "AES");
//Lookup an instance of a AES cipher
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
//initialize IV manually
byte[] ivBytes = new byte[]{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
//create IvParameterSpecobject
IvParameterSpec ivSpec = new IvParameterSpec(ivBytes);
//Initialize the cipher using the secter key
cipher.init(Cipher.ENCRYPT_MODE, keySpec,ivSpec);
//Message to encrypt
String plainText = "This is a secret!";
//Sequence of byte to encrypt
//Encrypt the message
byte[] cipherText = cipher.doFinal(plainText.getBytes());
System.out.println("Resulting Cipher Text:\n");
for(int i=0;i<cipherText.length;i++)
{
System.out.print(cipherText[i] + " ");
}
System.out.println("");
} catch (Exception e)
{
e.printStackTrace();
} } }
我希望使用SHA-1的输出,而不是手动设置IV 作为initialize IV,由于每次我有不同的整数值,我使用SHA-1获得固定长度,并在AES中将其重新用作initialize IV,例如:
input : 10
digest : b1d5781111d84f7b3fe45a0852e59758cd7a87e5
所以,AES代码需要16字节,SHA-1产生20字节,我怎样才能将20B转换成16字节的AES代码
如何重用:b1d5781111d84f7b3fe45a0852e59758cd7a87e5
而不是0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00
# 1 楼答案
不清楚您所说的“使用SHA-1的输出作为初始化IV”是什么意思。你散列了什么信息?这听起来像是默默无闻中的安全感
好的静脉注射应该是绝对随机和不可预测的,以确保安全
只需从
SecureRandom
中获取随机字节以用作IV:然后将生成的IV与密文一起存储在加密输出中
在解密过程中,首先读取IV,然后读取密文,然后解密