java数字代码
我有一个问题,让我告诉在给定的数字位数。我插入了条件语句,但无论插入什么数字,它都会给我“九”位数。代码如下。我是一名数学专业的学生,不是计算机科学专业的学生,所以我觉得我没有使用最有效的方法
import java.util.Scanner;
public class E52 {
public static void main(String[] args) {
// part 1: import scanner
Scanner sc = new Scanner(System.in);
// part 2: ask user for a number
System.out.println("Please enter a number: ");
int number = sc.nextInt();
// part 3: tell how many digits are in each number by using string and conditional statements
String number1Str;
if (number >= 0 || number <= 10) number1Str = "one";
if (number >= 10 || number <= 100) number1Str = "two";
if (number >= 100 || number <= 1000) number1Str= "three";
if (number >= 1000 || number <= 10000) number1Str = "four";
if (number >= 10000 || number <= 100000) number1Str = "five";
if (number >= 100000 || number <= 1000000) number1Str = "six";
if (number >= 1000000 || number <= 10000000) number1Str = "seven";
if (number >= 10000000 || number <= 100000000) number1Str = "eight";
if (number >= 100000000 || number <= 1000000000) number1Str = "nine";
else number1Str = "undefined";
System.out.println("There are " + number1Str + " digits in the given number.");
sc.close();
}
}
# 1 楼答案
创建一个数组,然后获取输入的长度并选择,让它选择条目,这会容易得多:
# 2 楼答案
这将给你数字计数,无论数字有多大或多小。虽然有一些角落的情况可能会失败的代码,但我仍然觉得这将是有用的,你在其他方面