在Java中将复杂字符串解析为整数集

Question

我是一名初级程序员，我的任务是计算打电话的总费用、一串电话号码和通话时间。对我来说，进行计算很容易，但是解析字符串本身却很有挑战性。我需要将包含分号、逗号和换行符的字符串转换为电话号码和总通话时间的整数集。字符串如下所示：

hh:mm:ss,nnn-nnn-nnn
hh:mm:ss,nnn-nnn-nnn
hh:mm:ss,nnn-nnn-nnn

我知道，如果我使用scanner和hasNext函数读取文本文件，我将能够逐行解析，那么我是否应该以某种方式利用\n？使用split(":")不会让我走多远

还有其他有用的吗？ 任何帮助或有用的信息都将不胜感激

Answer 1

对于这类任务，我更喜欢正则表达式和模式/匹配器：

        private static final String REGEX =
        "..:..:..,...-...-...";

    private static final String INPUT = "h1:m1:s1,nnn-nnn-nnn   \n"
            + "   h2:m2:s2,nnn-nnn-nnn   \n"
            + " hh:mm:ss,nnn-nnn-nnn";

    public static void main(String[] args) {
       Pattern p = Pattern.compile(REGEX);
       Matcher matcher = p.matcher(INPUT);
       while(matcher.find()) {
           String timePhoneNumber = matcher.group(0);
           String tokens[] = timePhoneNumber.split(",");
           String time = tokens[0];
           String phoneNumber = tokens[1];
           System.out.println("Time="+time+"; phone="+phoneNumber);
      }
   }

Answer 2

您可以使用split函数，只需使用"[]"指定每个要拆分的标记即可 例如，使用split("[ ,:-]")

密码

String number = "11:22:33,444-555-666";
String[] numbers = number.split("[ ,:-]");
for (String temp: numbers){
System.out.println(temp);

给出结果

11 22 33 444 555 666

Answer 3

public class MultiSplit {

    public static void main(final String[] args) {
        final String INPUT = "14:23:51,n11-n12-n13   \n"//
                + "   15:24:46,n21-n22-n23   \n" //
                + "   15:2a:46,n21-n22-n23   \n" // error
                + "\n" // error
                + "null\n" // error
                + " 12:11:10,n31-n32n33  \n" // error
                + " 12:1111,n31-n32n33  \n" // error
                + " 12:11:12,n31-n32-n33\n";

        final String[] dirtyLines = INPUT.split("\n");

        System.out.println("MODE 1");
        for (final String dirtyLine : dirtyLines) {
            try {
                final String cleanLine = dirtyLine.trim();
                final String line = cleanLine.replace(",", ":");
                final String[] parts = line.split(":");

                final int hour = Integer.parseInt(parts[0]);
                final int minute = Integer.parseInt(parts[1]);
                final int second = Integer.parseInt(parts[2]);
                final String phone = parts[3];
                System.out.println("h:" + hour + "\tm:" + minute + "\ts:" + second + " \t => " + phone);

            } catch (final Exception e) {
                System.err.println("Error on line <" + dirtyLine + ">: " + e);
            }
        }

        System.out.println("\n\nMODE 2");
        for (final String dirtyLine : dirtyLines) {
            try {
                final String cleanLine = dirtyLine.trim();
                final String line = cleanLine.replace(",", ":").replace("-", ":");
                final String[] parts = line.split(":");

                final int hour = Integer.parseInt(parts[0]);
                final int minute = Integer.parseInt(parts[1]);
                final int second = Integer.parseInt(parts[2]);
                final String phone1 = parts[3];
                final String phone2 = parts[4];
                final String phone3 = parts[5];
                System.out.println("h:" + hour + "\tm:" + minute + "\ts:" + second + " \t => " + phone1 + "#" + phone2 + "#" + phone3);

            } catch (final Exception e) {
                System.err.println("Error on line <" + dirtyLine + ">: " + e);
            }
        }

    }

}

Answer 4

您可以执行多个拆分，首先将时间与电话号码分开，然后将每个部分分开。例如：

Scanner sc = new Scanner(inputStr);

while (sc.hasNextLine()) {
    String line = sc.nextLine();
    String parts[] = line.split(",");
    String time[] = parts[0].split(":");
    String phone[] = parts[1].split("-");
    // Process the time and phone number here
}

可变部分有两个元素，时间和电话号码。可变时间包含时间的三个元素，phone包含电话号码的三个元素