java将学生添加到数组中
我已经想出了如何从用户那里收集数据,以便在我的数组中创建一个新的学生,但我在将这些信息添加到数组中时遇到了困难。请告诉我如何在给定代码中添加此数据作为新的学生对象。请参考AddStudent
方法
import java.util.Scanner;
public class ArrayDemo {
static Student[] students;
private static void ViewStudents() {
for (int i = 0; i < students.length; i++) {
System.out.println(i + ") " + students[i].getLName() + ", " + students[i].getFName());
}
}
private static void ViewDetails() {
Scanner kb = new Scanner(System.in);
int i;
System.out.println("Who would you like to view?");
ViewStudents();
i = Integer.parseInt(kb.nextLine());
System.out.println("ANum:\t\t" + students[i].getANum());
System.out.println("\nAddress:\t" + students[i].address.getHouseNum() + " " + students[i].address.getStreet());
System.out.println("\t\t" + students[i].address.getCity() + ", " + students[i].address.getState() + " " + students[i].address.getZip());
System.out.println("\t\t" + students[i].address.getLine2());
}
private static void AddStudent() {
Scanner kb = new Scanner(System.in);
Student student = new Student();
String FirstName;
String LastName;
int HouseNum;
String Street;
String City;
String State;
int Zip;
String Line2;
System.out.println("\tInput Information");
System.out.println("\tFirst Name:");
FirstName = kb.nextLine();
System.out.println("\tLast Name:");
LastName = kb.nextLine();
System.out.println("\tHouse Number:");
HouseNum = Integer.parseInt(kb.nextLine());
System.out.println("\tStreet:");
Street = kb.nextLine();
System.out.println("\tCity:");
City = kb.nextLine();
System.out.println("\tState:");
State = kb.nextLine();
System.out.println("\tZip Code:");
Zip = Integer.parseInt(kb.nextLine());
System.out.println("\tExtra Information:");
Line2 = kb.nextLine();
System.out.println("\nStudent:\t" + LastName + ", " + FirstName);
System.out.println("ANum:\t\t" + student.getANum());
System.out.println("Address:\t" + HouseNum + " " + Street);
System.out.println("\t\t" + City + ", " + State + " " + Zip);
System.out.println("\t\t" + Line2);
//students.setAddress( HouseNum, Street, City, State, Zip, Line2 );
System.out.println("\tYour Student was Successfully Added");
}
private static void RemoveStudent() {
Scanner kb = new Scanner(System.in);
System.out.println("Who would you like to remove?");
ViewStudents();
for (int j = Integer.parseInt(kb.nextLine()); j < students.length - 1; j++) {
students[j] = students[j + 1];
}
students[students.length - 1] = null;
}
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
int x = 40;
//students = new Student[0];
students = new Student[2];
students[0] = new Student("Thomas", "Emily");
students[1] = new Student("Bob", "Joe");
students[0].address = new Address(6614, "White Sands ln", "Hixson", "Tennessee", 37343, "");
students[1].address = new Address(66, "White ln", "Hson", "Tealamabaee", 373873, "");
do {
System.out.println();
System.out.println("Do you want to:");
System.out.println("\t0) View Students");
System.out.println("\t1) View Students' Details");
System.out.println("\t2) Add a Student");
System.out.println("\t3) Remove a Student");
System.out.println("\t4) Exit");
x = Integer.parseInt(kb.nextLine());
switch (x) {
case 0:
ViewStudents();
break;
case 1:
ViewDetails();
break;
case 2:
AddStudent();
break;
case 3:
RemoveStudent();
break;
case 4:
break;
default:
}
} while (x != 4);
}
}
# 1 楼答案
从我看来,你使用了错误的数据结构。你似乎知道,添加动态数量的
Student
和ArrayList
比Array
好得多,也更合适。然后你可以简单地使用add
方法记住,一个
Array
的大小是不变的(它不能改变),所以在这种情况下,你想要的肯定是某种List
,可能是ArrayList
如果坚持使用数组,则需要跟踪学生已经添加的数量,并将其用作索引(作为全局变量或作为参数传递)。但是要记住
Array
的性质意味着你会很快达到上限,除非你设置了非常高的容量