从url下载json文件时java连接超时

Question

我试图从Java中的以下URL下载JSON文件：http://map01.eniro.no/search/search.json?index=yp&profile=pl&q=ma%C5%82opolskie&sortOrder=default&pageSize=5，但我总是遇到一个异常：

HTTP Status 500 - Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
type Exception report
message Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
description The server encountered an internal error that prevented it from fulfilling this request.
exception
java.io.IOException: Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
    sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
    sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    java.lang.reflect.Constructor.newInstance(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection$10.run(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection$10.run(Unknown Source)
    java.security.AccessController.doPrivileged(Native Method)
    sun.net.www.protocol.http.HttpURLConnection.getChainedException(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    MainServlet.callURL(MainServlet.java:108)
    MainServlet.doGet(MainServlet.java:71)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
root cause
java.io.IOException: Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
    sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    java.net.HttpURLConnection.getResponseCode(Unknown Source)
    MainServlet.callURL(MainServlet.java:102)
    MainServlet.doGet(MainServlet.java:71)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

这是我的职责。我尝试了很多不同的方法来解决这个问题，但我总是得到相同的结果。我没有太多的HTTP连接编程经验，所以我需要帮助

public static void callURL() throws IOException {

    URL obj = new URL("http://map01.eniro.no/search/search.json");
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/43.0.2357.124 Safari/537.36");
    con.setRequestProperty("Accept-Language", "pl-PL;q=0.8");

    String urlParameters = "?index=yp&profile=pl&q=małopolskie&sortOrder=default&pageSize=5";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + myURL);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    System.out.println(response.toString());
}

更新：

我通过Fiddler应用程序检查了我的http请求，发现其中有一个错误：

“请求行格式不正确。abs_路径为空（例如，缺少/）。RFC2616'

这是什么意思？我认为这个请求是正确的，因为在浏览器中我可以阅读这个json