string希望使用java内置方法删除空白

Question

我开发了一个应用程序，可以读取java项目中一个java包中有多少个文件，并计算这些单独文件中的代码行，例如在一个java项目中，如果有两个包中有4个单独的文件，那么读取的文件总数将是4，如果这4个文件中有10行代码那么4*10是整个项目中总共40行代码。。。下面是我的一段代码

     private static int totalLineCount = 0;
        private static int totalFileScannedCount = 0;

        public static void main(final String[] args) throws FileNotFoundException {

            JFileChooser chooser = new JFileChooser();
            chooser.setCurrentDirectory(new java.io.File("C:" + File.separator));
            chooser.setDialogTitle("FILES ALONG WITH LINE NUMBERS");
            chooser.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY);
            chooser.setAcceptAllFileFilterUsed(false);
            if (chooser.showOpenDialog(null) == JFileChooser.APPROVE_OPTION) {
                Map<File, Integer> result = new HashMap<File, Integer>();
                File directory = new File(chooser.getSelectedFile().getAbsolutePath());

                List<File> files = getFileListing(directory);

                // print out all file names, in the the order of File.compareTo()
                for (File file : files) {
                   // System.out.println("Directory: " + file);
                    getFileLineCount(result, file);
                    //totalFileScannedCount += result.size(); //saral
                }

                System.out.println("*****************************************");
                System.out.println("FILE NAME FOLLOWED BY LOC");
                System.out.println("*****************************************");

                for (Map.Entry<File, Integer> entry : result.entrySet()) {
                    System.out.println(entry.getKey().getAbsolutePath() + " ==> " + entry.getValue());
                }
                System.out.println("*****************************************");
                System.out.println("SUM OF FILES SCANNED ==>" + "\t" + totalFileScannedCount);
                System.out.println("SUM OF ALL THE LINES ==>" + "\t" + totalLineCount);
            }

        }

        public static void getFileLineCount(final Map<File, Integer> result, final File directory)
                throws FileNotFoundException {
            File[] files = directory.listFiles(new FilenameFilter() {

                public boolean accept(final File directory, final String name) {
                    if (name.endsWith(".java")) {
                        return true;
                    } else {
                        return false;
                    }
                }
            });
            for (File file : files) {
                if (file.isFile()) {
                    Scanner scanner = new Scanner(new FileReader(file));
                    int lineCount = 0;
                    totalFileScannedCount ++; //saral
                    try {
                        for (lineCount = 0; scanner.nextLine() != null; ) {
                            while (scanner.hasNextLine()) {
   String line = scanner.nextLine().trim();
   if (!line.isEmpty()) {
     lineCount++;
   }
                        }
                    } catch (NoSuchElementException e) {
                        result.put(file, lineCount);
                        totalLineCount += lineCount;
                    }
                }
            }

        }

        /**
         * Recursively walk a directory tree and return a List of all Files found;
         * the List is sorted using File.compareTo().
         * 
         * @param aStartingDir
         *            is a valid directory, which can be read.
         */
        static public List<File> getFileListing(final File aStartingDir) throws FileNotFoundException {
            validateDirectory(aStartingDir);
            List<File> result = getFileListingNoSort(aStartingDir);
            Collections.sort(result);
            return result;
        }

        // PRIVATE //
        static private List<File> getFileListingNoSort(final File aStartingDir) throws FileNotFoundException {
            List<File> result = new ArrayList<File>();
            File[] filesAndDirs = aStartingDir.listFiles();
            List<File> filesDirs = Arrays.asList(filesAndDirs);
            for (File file : filesDirs) {
                if (file.isDirectory()) {
                    result.add(file);
                }
                if (!file.isFile()) {
                    // must be a directory
                    // recursive call!
                    List<File> deeperList = getFileListingNoSort(file);
                    result.addAll(deeperList);
                }
            }
            return result;
        }

        /**
         * Directory is valid if it exists, does not represent a file, and can be
         * read.
         */
        static private void validateDirectory(final File aDirectory) throws FileNotFoundException {
            if (aDirectory == null) {
                throw new IllegalArgumentException("Directory should not be null.");
            }
            if (!aDirectory.exists()) {
                throw new FileNotFoundException("Directory does not exist: " + aDirectory);
            }
            if (!aDirectory.isDirectory()) {
                throw new IllegalArgumentException("Is not a directory: " + aDirectory);
            }
            if (!aDirectory.canRead()) {
                throw new IllegalArgumentException("Directory cannot be read: " + aDirectory);
            }
        }

但问题是，在计算单个文件的代码行时，它也会计算空白行，这是不应该的。请告知我需要在我的程序中进行哪些修改，以便在计算单个文件的代码行时，它不会计算空白行

我脑海中浮现的想法是将读取的字符串与“”进行比较，如果不等于“”（空），则计数，比如if（！readString.trim（）。等于（“”）行数++ 请对此提出建议