测试1上的java运行时错误（代码强制），但在netbeans中有效

Question

我不熟悉代码强制，当我在NetBeans中运行此代码时，它可以正常工作，但当我在代码强制上提交它时，它会在测试1中给我运行时错误。怎么了？ 这是problem

import java.util.Scanner;

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    String first = input.nextLine();
    String second = input.nextLine();
    input.close();

    String first_line[] = first.split(" ");
    String second_line[] = second.split(" ");
    int first_numbers[] = new int[first_line.length];
    int second_numbers[] = new int[second_line.length];

    for (int i = 0; i < 2; i++) {
        if (Integer.parseInt(first_line[i]) >= 1)
            first_numbers[i] = Integer.parseInt(first_line[i]);
        else
            first_numbers[i] = 0;
    }
    for (int i = 0; i < second_line.length; i++)
        if (Integer.parseInt(second_line[i]) >= 1)
            second_numbers[i] = Integer.parseInt(second_line[i]);
        else
            second_numbers[i] = 0;
    int x = 0;
    try {
        for (int i = 0; first_numbers[1] < second_numbers[i]; i++)
            x++;
    } catch (Exception ex) {

    }
    System.out.println(x);
}

Answer 1

为什么要把字符串拆分成这些

   String first_line[] = first.split(" ");
   String second_line[] = second.split(" ");
   int first_numbers[] = new int[first_line.length];
   int second_numbers[] = new int[second_line.length];

您可以从一开始就初始化int，并按如下方式使用它

        Scanner input = new Scanner(System.in);
        int k = input.nextInt();
        int n = input.nextInt();
        int cout = 0;
        int[] arr = new int[k];

这是我从2014年开始对这个问题的完整解决方案

public static void main(String[] args) {

        Scanner input = new Scanner(System.in);
        int n = input.nextInt();
        int k = input.nextInt();
        int counter = 0, tk = 0;
        int a[] = new int[n];

        for(int i = 0; i < n; ++i){
            a[i] = input.nextInt();
            if((i + 1) == k){
                tk = a[i];
            }
        }

        for(int i = 0; i < n; ++i){
            if(a[i] > 0 && a[i] >= tk){
                counter++;
            }
        }

        System.out.println(counter);
    }

我希望我能帮忙

如果我能建议你 在开始的时候，尽可能地简化这些问题

Answer 2

如果您修改最后一个for循环，如下所示，该怎么办

int x = 0;
for (int i=0; i<second_numbers.length; i++) {
    if (first_numbers[1] < second_numbers[i])
        x++;
}