java需要帮助遍历HashMap的ArrayList
我需要循环一个ArrayList,寻找一个特定的“keys”HashMap,并返回相应的“params”HashMap,如屏幕截图所示
这是我目前所拥有的,但它不起作用
private void getParam() {
List<Map<String, Object>> matrix = transactionInfoMatrix.getMatrixTransactionInfo();
MatrixTransactionInfoKeys key = new MatrixTransactionInfoKeys("OP/OP", "2777", "CT", "NBCTRANSFER", "AMT");
for (Map<String, Object> entry : matrix) {
if (entry.containsValue(key)) {
System.out.println("Found it");
}
}
}
这是MatrixTransactionInfoKeys类,但为了本文的目的,我删除了getter和setter
public class MatrixTransactionInfoKeys {
private String accountType;
private String applicationSourceCode;
private String operationType;
private String service;
private String transactionType;
public MatrixTransactionInfoKeys(String accountType, String applicationSourceCode, String operationType, String service, String transactionType) {
this.accountType = accountType;
this.applicationSourceCode = applicationSourceCode;
this.operationType = operationType;
this.service = service;
this.transactionType = transactionType;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((accountType == null) ? 0 : accountType.hashCode());
result = prime * result + ((applicationSourceCode == null) ? 0 : applicationSourceCode.hashCode());
result = prime * result + ((operationType == null) ? 0 : operationType.hashCode());
result = prime * result + ((service == null) ? 0 : service.hashCode());
result = prime * result + ((transactionType == null) ? 0 : transactionType.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
}
if (obj == null) {
return false;
}
if (getClass() != obj.getClass()) {
return false;
}
MatrixTransactionInfoKeys other = (MatrixTransactionInfoKeys) obj;
if (accountType == null) {
if (other.accountType != null) {
return false;
}
} else if (!accountType.equals(other.accountType)) {
return false;
}
if (applicationSourceCode == null) {
if (other.applicationSourceCode != null) {
return false;
}
} else if (!applicationSourceCode.equals(other.applicationSourceCode)) {
return false;
}
if (operationType == null) {
if (other.operationType != null) {
return false;
}
} else if (!operationType.equals(other.operationType)) {
return false;
}
if (service == null) {
if (other.service != null) {
return false;
}
} else if (!service.equals(other.service)) {
return false;
}
if (transactionType == null) {
return other.transactionType == null;
} else
return transactionType.equals(other.transactionType);
}
@Override
public String toString() {
return "MatrixTransactionInfoKeys [service=" + service + ", applicationSourceCode=" + applicationSourceCode
+ ", transactionType=" + transactionType + ", operationType=" + operationType + ", accountType=" + accountType + "]";
}
}
# 1 楼答案
重新设计这个答案,因为我最初误解了这个问题
根据提供的代码,假设映射中的
MatrixTransactionInfoKeys
实际上匹配,并且创建方式类似,我在以下输出中得到“find it”: