java将这个字符串转换成字符串数组的最佳方法是什么？

Question

我正在实现一个游戏服务器，并将游戏板表示为一个字符串，以这个状态为例：

String b = ", a36, a32, a26, a40, a295, a41, a49, /, , a16, a09, a68, a11, a99, ,"

我想将此字符串转换为以下字符串数组：

[, a36, a32, a26, a40, a295, a41, a49, , , , a16, a09, a68, a11, a99, ]

我试着使用String.split：

String[] bArray = b.split("/|,");

这将产生：

boardArray = [, a36, a32, a26, a40, a295, a41, a49, , , , a16, a09, a68, a11, a99]

它切断了数组中我想要的最后一个" "元素。修改代码并手动添加最后一个元素后：

String[] bArray = b.split("/|,");
bArray = Arrays.copyOf(bArray, bArray.length + 1);
bArray[bArray.length - 1] = "";

这给了我正确的结果，但这个解决方案效率低下。有人知道如何更干净地做这件事吗

Answer 1

试试这个：

b.split("/|,", -1);

这与极限参数（第二个）分开，正如documenation所说：

The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter. If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.

Answer 2

尝试加载到List<String>并遍历该列表

String b = ", a36, a32, a26, a40, a295, a41, a49, /, , a16, a09, a68, a11, a99, ,";
List<String> myList = Arrays.asList(b.split(","));
System.out.println(myList);

输出：

[,  a36,  a32,  a26,  a40,  a295,  a41,  a49,  /,  ,  a16,  a09,  a68,  a11,  a99,  ]