java我的HTTP表单登录程序中的错误在哪里？
我试图通过发布带有http请求的登录值来查看受保护的html页面。。。该网站是sportguru。co.uk和我似乎无法正确发布密码！？当我运行此代码时（使用我的实际登录详细信息）：
/**
* $Id: LoginByHttpPost.java 101 2010-03-13 23:52:31Z oneyour $
*
* This is an accompanying program for the article
* http://www.1your.com/drupal/LoginToWebsiteByHTTPPOSTCodeListing
*
* Copyright (c) 2009 - 2010 www.1your.com. All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
*
* - Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
*
* - Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
*
* - Neither the name of www.1your.com nor the names of its
* contributors may be used to endorse or promote products derived
* from this software without specific prior written permission.
*
* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS
* IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO,
* THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
* PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR
* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
* EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
* PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF
* LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING
* NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
* SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*
*/
import java.net.*;
import java.io.*;
public class LoginByHttpPost
{
private static final String POST_CONTENT_TYPE = "application/x-www-form-urlencoded";
private static final String LOGIN_ACTION_NAME = "Log in";
private static final String LOGIN_USER_NAME_PARAMETER_NAME = "email";
private static final String LOGIN_PASSWORD_PARAMETER_NAME = "password";
private static final String LOGIN_USER_NAME = "emailAddress";
private static final String LOGIN_PASSWORD = "password";
private static final String TARGET_URL = "http://www.sportguru.co.uk/login_form.asp";
public static void main (String args[])
{
System.out.println("About to run the 'LogInByHttpPost' downloaded from www.1Your.com");
LoginByHttpPost httpUrlBasicAuthentication = new LoginByHttpPost();
httpUrlBasicAuthentication.httpPostLogin();
}
/**
* The single public method of this class that
* 1. Prepares a login message
* 2. Makes the HTTP POST to the target URL
* 3. Reads and returns the response
*
* @throws IOException
* Any problems while doing the above.
*
*/
public void httpPostLogin ()
{
try
{
// Prepare the content to be written
// throws UnsupportedEncodingException
String urlEncodedContent = preparePostContent(LOGIN_USER_NAME, LOGIN_PASSWORD);
HttpURLConnection urlConnection = doHttpPost(TARGET_URL, urlEncodedContent);
String response = readResponse(urlConnection);
System.out.println("Successfully made the HTPP POST.");
System.out.println("Recevied response is: '/n" + response + "'");
System.out.println("/n Hope you found the article and this sample program useful./nPlease leave your feed back at www.1your.com and support us.");
}
catch(IOException ioException)
{
System.out.println("Problems encounterd.");
}
}
/**
* Using the given username and password, and using the static string variables, prepare
* the login message. Note that the username and password will encoded to the
* UTF-8 standard.
*
* @param loginUserName
* The user name for login
*
* @param loginPassword
* The password for login
*
* @return
* The complete login message that can be HTTP Posted
*
* @throws UnsupportedEncodingException
* Any problems during URL encoding
*/
private String preparePostContent(String loginUserName, String loginPassword) throws UnsupportedEncodingException
{
// Encode the user name and password to UTF-8 encoding standard
// throws UnsupportedEncodingException
String encodedLoginUserName = URLEncoder.encode(loginUserName, "UTF-8");
String encodedLoginPassword = URLEncoder.encode(loginPassword, "UTF-8");
String content = "Log in=" + LOGIN_ACTION_NAME +" &" + LOGIN_USER_NAME_PARAMETER_NAME +"="
+ encodedLoginUserName + "&" + LOGIN_PASSWORD_PARAMETER_NAME + "=" + encodedLoginPassword;
return content;
}
/**
* Makes a HTTP POST to the target URL by using an HttpURLConnection.
*
* @param targetUrl
* The URL to which the HTTP POST is made.
*
* @param content
* The contents which will be POSTed to the target URL.
*
* @return
* The open URLConnection which can be used to read any response.
*
* @throws IOException
*/
public HttpURLConnection doHttpPost(String targetUrl, String content) throws IOException
{
HttpURLConnection urlConnection = null;
DataOutputStream dataOutputStream = null;
try
{
// Open a connection to the target URL
// throws IOException
urlConnection = (HttpURLConnection)(new URL(targetUrl).openConnection());
// Specifying that we intend to use this connection for input
urlConnection.setDoInput(true);
// Specifying that we intend to use this connection for output
urlConnection.setDoOutput(true);
// Specifying the content type of our post
urlConnection.setRequestProperty("Content-Type", POST_CONTENT_TYPE);
// Specifying the method of HTTP request which is POST
// throws ProtocolException
urlConnection.setRequestMethod("POST");
// Prepare an output stream for writing data to the HTTP connection
// throws IOException
dataOutputStream = new DataOutputStream(urlConnection.getOutputStream());
// throws IOException
dataOutputStream.writeBytes(content);
dataOutputStream.flush();
dataOutputStream.close();
return urlConnection;
}
catch(IOException ioException)
{
System.out.println("I/O problems while trying to do a HTTP post.");
ioException.printStackTrace();
// Good practice: clean up the connections and streams
// to free up any resources if possible
if (dataOutputStream != null)
{
try
{
dataOutputStream.close();
}
catch(Throwable ignore)
{
// Cannot do anything about problems while
// trying to clean up. Just ignore
}
}
if (urlConnection != null)
{
urlConnection.disconnect();
}
// throw the exception so that the caller is aware that
// there was some problems
throw ioException;
}
}
/**
* Read response from the URL connection
*
* @param urlConnection
* The URLConncetion from which the response will be read
*
* @return
* The response read from the URLConnection
*
* @throws IOException
* When problems encountered during reading the response from the
* URLConnection.
*/
private String readResponse(HttpURLConnection urlConnection) throws IOException
{
BufferedReader bufferedReader = null;
try
{
// Prepare a reader to read the response from the URLConnection
// throws IOException
bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
String responeLine;
// Good Practice: Use StringBuilder in this case
StringBuilder response = new StringBuilder();
// Read untill there is nothing left in the stream
// throws IOException
while ((responeLine = bufferedReader.readLine()) != null)
{
response.append('\n'+responeLine);
}
return response.toString();
}
catch(IOException ioException)
{
System.out.println("Problems while reading the response");
ioException.printStackTrace();
// throw the exception so that the caller is aware that
// there was some problems
throw ioException;
}
finally
{
// Good practice: clean up the connections and streams
// to free up any resources if possible
if (bufferedReader != null)
{
try
{
// throws IOException
bufferedReader.close();
}
catch(Throwable ignore)
{
// Cannot do much with exceptions doing clean up
// Ignoring all exceptions
}
}
}
}
}
我收到的HTML页面包含以下表单：
<form name="loginPage" method="post" action="login.asp" onSubmit="return submitForm()" style="margin:0px;padding:0px">
<input type="hidden" name="pageReferer" value="" />
<input type="hidden" name="logintype" value="page" />
<input type="hidden" name="pagePoolCode" value="" />
<div style="border:2px solid #666666;width:486px">
<div style="background-image:url(home/images/structure/header_login.gif);height:28px;"></div>
<div style="padding:7px;">
<table cellspacing="2" cellspacing="0">
<tr>
<td align="right" width="62">Email:</td>
<td><input type="text" name="pageEmail" value="emailAddress" size="32"></td>
</tr>
<tr>
<td align="right">Password:</td>
<td><input type="password" name="pagePassword" size="32"></td>
</tr>
<tr>
<td align="right"></td>
<td class="small"><a href="forgotten.asp"><strong>Forgotten</strong> your email address or password? Or has your<br /><strong>email changed</strong> since last you used the site? <strong>Click here</strong> »</a></td>
</tr>
<tr>
<td> </td>
<td style="padding-top:7px;"><input type="image" src="/home/images/buttons/login.gif" value="Log in"></td>
</tr>
</table>
</div>
</div>
</form>
可以看出，电子邮件地址已正确地发布到表单中。但我希望在发布后查看html页面的源代码。。。我需要饼干什么的吗
# 1 楼答案
你查过HTTP状态码了吗？可能会有重定向
# 2 楼答案
你认为
Log in中真的应该有一个空格吗也许
Log%20in或Log+in在这里会更好。（由于我没有看到你的完整表格，我只能在这里猜测。）因此，我们必须发送这些表单字段：
pageReferer（空）logintype（page）pagePoolCode（空）pageEmail（电子邮件地址？）pagePassword（密码？）还有一个
<input type="image" src="/home/images/buttons/login.gif" value="Log in">，但它没有name属性，因此无法发送。所以，我的第一个猜测就是在内容字符串中省略这个"Log in="部分如果这不起作用，请将前三个字段也添加到字符串中：