Java/Android不允许将“this”作为意图声明中的参数

Question

我在私有类中的受保护函数中定义意图。我是Java/Android新手，不知道如何将参数传递给Intent。我一直在其他活动中使用“this”，但我收到AndroidStudio的投诉

Intent setSession = new Intent(this, posterSessionSetup.class);

Cannot resolve constructor Intent(.....

 private class AsyncCaller extends AsyncTask<String, Void, String> {
        protected String doInBackground(String... urls) {
            //get the text input and validate it
            EditText userName = (EditText)findViewById(R.id.txtUserName);
            EditText password = (EditText)findViewById(R.id.passWord);

            return readJSONFeed("mywebservice", userName.getText().toString(), password.getText().toString());
        }
        protected void onPostExecute(String result){
            try {
                JSONObject jsonObject = new JSONObject(result);
                JSONObject r = new JSONObject(jsonObject.getString("r"));
                String status = r.getString("status");
                String msg = r.getString("msg");
                if (status == "complete"){
    --------->>>>>> Intent setSession = new Intent(this, posterSessionSetup.class);
                    startActivity(setSession);
                }
                else {
                    Toast.makeText(getBaseContext(), r.getString("status") + ":" + r.getString("msg"), Toast.LENGTH_SHORT).show();
                }
            } catch(Exception e){
                Log.d("Read Json File", e.getLocalizedMessage());
            }

        }

    }

Answer 1

这里指的是异步任务

Uae活动或该类嵌入的任何内容

Answer 2

你在the inner classAsyncCaller所以this指的是那个类。如果外部类名为YourActivityClass，则可以使用YourActivityClass.this来引用外部类