java 安卓千位分隔符和两位小数
我需要一些帮助,因为我无法在安卓 studio中获得所需的工作
我有一个EditText,我想在用户写入时用逗号将其分隔为数千(onTextChange),同时将其限制为小数点后2或8位
到目前为止,我已经能够通过放置“,”将输入分隔成数千个,我还能够使用InputFilter限制小数位数,但每一个都是单独的,我无法同时执行一组操作,即“千位分隔符”和“限制小数位数”。有人能帮我吗
通过下面的操作,我得到了千位分隔符
import 安卓.text.Editable;
import 安卓.text.TextWatcher;
import 安卓.util.Log;
import 安卓.widget.EditText;
import java.util.StringTokenizer;
public class NumberTextWatcherForThousand implements TextWatcher {
EditText editText;
public NumberTextWatcherForThousand(EditText editText) {
this.editText = editText;
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
try
{
editText.removeTextChangedListener(this);
String value = editText.getText().toString();
if (value != null && !value.equals(""))
{
if(value.startsWith(".")){
editText.setText("0.");
}
if(value.startsWith("0") && !value.startsWith("0.")){
editText.setText("");
}
String str = editText.getText().toString().replaceAll(",", "");
if (!value.equals(""))
editText.setText(getDecimalFormattedString(str));
editText.setSelection(editText.getText().toString().length());
}
editText.addTextChangedListener(this);
return;
}
catch (Exception ex)
{
ex.printStackTrace();
editText.addTextChangedListener(this);
}
}
public static String getDecimalFormattedString(String value)
{
StringTokenizer lst = new StringTokenizer(value, ".");
String str1 = value;
String str2 = "";
if (lst.countTokens() > 1)
{
str1 = lst.nextToken();
str2 = lst.nextToken();
}
String str3 = "";
int i = 0;
int j = -1 + str1.length();
if (str1.charAt( -1 + str1.length()) == '.')
{
j--;
str3 = ".";
}
for (int k = j;; k--)
{
if (k < 0)
{
if (str2.length() > 0)
str3 = str3 + "." + str2;
return str3;
}
if (i == 3)
{
str3 = "," + str3;
i = 0;
}
str3 = str1.charAt(k) + str3;
i++;
}
}
public static String trimCommaOfString(String string) {
// String returnString;
if(string.contains(",")){
return string.replace(",","");}
else {
return string;
}
}
}
我用这个限制小数
public class DecimalDigitsInputFilter implements InputFilter {
Pattern mPattern;
public DecimalDigitsInputFilter(int digitsBeforeZero,int digitsAfterZero) {
mPattern=Pattern.compile("[0-9]{0," + (digitsBeforeZero-1) + "}+((\\.[0-9]{0," + (digitsAfterZero-1) + "})?)||(\\.)?");
}
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
Matcher matcher=mPattern.matcher(dest);
if(!matcher.matches())
return "";
return null;
}
}
public static Double formatdecimal(Double num, Integer numdecimal) {
return Math.round(num* Math.pow(10, numdecimal)) / Math.pow(10, numdecimal);
}
第一个用于分隔千,第二个用于限制小数,但我找不到我需要的方法,我想限制小数并按千分隔
共 (0) 个答案