oop对随机生成的Java数字有问题

Question

我正在研究Joyce Farrell的Java编程书中的这个项目，我对随机生成的数字和用户的猜测没有被正确检查有一个问题。例如，用户有3次猜测，假设他们的第一次猜测是2，第一个随机生成的数字是2，程序将打印出你输了。当猜测是正确的时候。请帮帮我。我已经添加了该计划的细节，以及我迄今为止所做的工作

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创建彩票游戏应用程序。生成三个随机数（参见附录D中的帮助 这样做），每个都在0到9之间。允许用户猜测三个数字。比较每一个 用户对三个随机数的猜测，并显示一条消息，其中包括用户的 猜猜，随机确定的三位数，以及用户拥有的金额 赢了如下

配对号码奖（元）

任何一个匹配10 两个匹配100 三个匹配，不是为了1000 三个完全匹配，顺序是1000000

没有对手0

确保应用程序中包含重复的数字。例如，如果用户 猜测1、2和3，并且随机生成的数字是1、1和1，不会给用户 有三个正确的猜测——只有一个。将文件另存为彩票

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我的源代码

// Filename: Lottery.java
// Written by: Andy A
// Written on: 14 January 2015

import java.util.Scanner;
import java.util.Random;

public class Lottery {

    public static void main(String[] args) {

        Scanner userInput = new Scanner(System.in);
        Random ranNum = new Random();

        // LIMIT Contains The Numbers From 0 - 9
        // TIMES Contains The Number of Time ranNum Should Run
        final int LIMIT = 9;
        final int TIMES = 3;

        // Users Guesses
        int usersFirstGuess;
        int usersSecondGuess;
        int usersThirdGuess;

        // Randomly Generated Numbers
        final int GenFirst = ranNum.nextInt(LIMIT);
        final int GenSecond = ranNum.nextInt(LIMIT);
        final int GenThird = ranNum.nextInt(LIMIT);

        // User is asked for 3 guesses
        System.out.println("Please enter your first guess: ");
        usersFirstGuess = userInput.nextInt();
        System.out.println("Please enter your second guess: ");
        usersSecondGuess = userInput.nextInt();
        System.out.println("Please enter your third and final guess: ");
        usersThirdGuess = userInput.nextInt();

        // Winning Amounts
        final double WinTen = 10;
        final double WinHun = 100;
        final double WinThund = 1000;
        final double WinMillion = 1000000;
        final int WinZero = 0;

        // Shows the randomly generated numbers
        for(int x = 0; x < TIMES; ++x)
            System.out.print(ranNum.nextInt(LIMIT) + " ");
        System.out.println();

        // First Generated
        if(GenFirst == usersFirstGuess ) {
            System.out.println("You have won: $" + WinTen);
        }
            else if(GenSecond == usersSecondGuess) {
                    System.out.println("You have won: $" + WinTen);
            }
            else if(GenThird == usersThirdGuess) {
                System.out.println("You have won: $" + WinTen);
            }
    }
}

Answer 1

您正在使用ranNum.nextInt(LIMIT)打印新生成的数字，但是您正在将用户输入与GenXXX变量中存储的数字进行比较

解决方案：打印变量

System.out.println(GenFirst + " " + GenSecond + " " + GenThird);

如果仍要使用循环打印，可以将数字存储在数组中

// generate
final int[] generated = new int[TIMES];
for (int x = 0; x < TIMES; x++)
    generated[x] = ranNum.nextInt(LIMIT);

// print
for (int x = 0; x < TIMES; x++)
    System.out.print(generated[x] + " ");

Answer 2

没错， 你为什么要打印

System.out.print(ranNum.nextInt(LIMIT) + " ");

当你应该只是打印的时候

System.out.print(GenThird + " ");
System.out.print(GenSecond + " ");
System.out.print(GenFirst + " ");

Answer 3

这应该能奏效

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// Filename: Lottery.java
// Written by: Andy A
// Written on: 14 January 2015

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
import java.util.Random;

public class Lottery {

    public static void main(String[] args) {

        Scanner userInput = new Scanner(System.in);
        Random ranNum = new Random();

        // LIMIT Contains The Numbers From 0 - 9
        // TIMES Contains The Number of Time ranNum Should Run
        final int LIMIT = 9;
        final int TIMES = 3;

        // Users Guesses
        int usersFirstGuess;
        int usersSecondGuess;
        int usersThirdGuess;
        List<Integer> guesses = new ArrayList<>();

        // Randomly Generated Numbers
        final int GenFirst = ranNum.nextInt(LIMIT);
        final int GenSecond = ranNum.nextInt(LIMIT);
        final int GenThird = ranNum.nextInt(LIMIT);

        // User is asked for 3 guesses
        System.out.println("Please enter your first guess: ");
        usersFirstGuess = userInput.nextInt();
        guesses.add(usersFirstGuess);
        System.out.println("Please enter your second guess: ");
        usersSecondGuess = userInput.nextInt();
        guesses.add(usersSecondGuess);
        System.out.println("Please enter your third and final guess: ");
        usersThirdGuess = userInput.nextInt();
        guesses.add(usersThirdGuess);

        // Winning Amounts
        final double WinTen = 10;
        final double WinHun = 100;
        final double WinThund = 1000;
        final double WinMillion = 1000000;
        final int WinZero = 0;

        // Shows the randomly generated numbers
        System.out.println(GenFirst + " " + GenSecond + " " + GenThird);
        List<Integer> lottery = new ArrayList<>();
        lottery.add(GenFirst);
        lottery.add(GenSecond);
        lottery.add(GenThird);

        if (guesses.equals(lottery)) {
            System.out.println("You have won: $" + WinMillion);
        } else {
            int matchCount = 0;
            for (Integer guessValue : guesses) {
                if (lottery.contains(guessValue)) {
                    matchCount++;
                    lottery.remove(guessValue);
                }
            }

            switch (matchCount) {
                case 0:
                    System.out.println("You have won: $" + WinZero);
                    break;
                case 1:
                    System.out.println("You have won: $" + WinTen);
                    break;
                case 2:
                    System.out.println("You have won: $" + WinHun);
                    break;
                case 3:
                    System.out.println("You have won: $" + WinThund);
                    break;
            }
        }
    }
}

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Answer 4

这不是随机生成的数字的问题，而是如果你想用你的方式向用户展示它们

在if / else if语句之前，在for循环中生成新的随机数。这意味着，与用户输入（genFirst）相比的数字可以是3，但在for循环中向用户显示的数字是一个新的随机数，例如2

要解决此问题，应显示生成的数字，如下所示：

for (int ranInt : new int[] { GenFirst, GenSecond, GenThird}) {
    System.out.println(ranInt);
}

这段代码创建了一个生成的数字数组，并在其中循环打印它们。显然，你也可以print GenFirst，然后print GenSecond，然后print GenThird

我希望这有帮助