charat如何在小于和大于之间查找文本，然后在Java中剥离<>？

Question

我不知道怎么找到这些词。。例如，我有这个文本

The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> .

当我在google上搜索<和>时，我不知道搜索原因是什么，它将被忽略。需要如何获取此字符串的帮助

所以我将得到<location>，<plural-noun>，<location>，<adjective>，<location>

我必须使用charAt()方法。我的尝试：

String string = this.fileName;
for(int i = 0; i < string.length(); i++)
                if((string.charAt(i) == '<') && (string.charAt(i) == '>'))
                    System.println(""); //<-------- IM STUCK HERE

我不知道。。。几乎两天没有睡觉

我现在还有最后一个问题。。。如何删除显示的每个单词上的<和>

String string = this.template;
        Pattern pattern = Pattern.compile("<.*?>");
        Matcher matcher = pattern.matcher(string);

        List<String> listMatches = new ArrayList<String>();

        while(matcher.find()) {
            listMatches.add(matcher.group());
        }
        // System.out.println(listMatches.size());
        int indexNumber = 1;
         for(String s : listMatches) {
             System.out.println(Integer.toString(indexNumber) + ". " + s);
             indexNumber++;
         }

Answer 1

阅读整行内容并将其存储在String line中。然后，使用：

String line = "The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> ."; 

boolean found = false;
String data[] = new String[20];
int counter = 0;

Arrays.fill(data, "");

for(int i = 0; i < line.length() && counter < 20; i++) {
    if(line.charAt(i) == '<')
        found = true;
    else if(line.charAt(i) == '>' && found) {
        found = false;
        counter++;
    }
    else if(found) {
        data[counter] += line.charAt(i);
    }
}

for(int i = 0; i < counter; i++)
    System.out.println("Scanned data #" + (i + 1) + " = " + data[i]);

Answer 2

这里有两个问题，所以我只回答最后一个；当您拥有所需的<text>时，按如下方式操作：

String text = "<the_text_you_want>";

text.replace("<","").replace(">","").replace("-"," ");

这将去掉分隔符

Answer 3

您可以使用Pattern和Matcher类

1. 搜索正则表达式模式<.*?>
2. 使用Matcher查找模式