Java忽略字符串

Question

我是编程新手，这个问题总是摆在我面前 当我运行程序时，Java会忽略if中的字符串输入 我做错了什么

import java.util.Scanner;

public class JavaApplication {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        System.out.print("------ FEEDBACK/COMPLAINT ------\n"
                + "-------------------------------------\n"
                + "| 1: Submit Feedback |\n"
                + "| 2: Submit Complaint |\n"
                + "| 3: Previous Menu |\n"
                + "-----------------------------------\n"
                + "> Please enter the choice: ");
        int feedorcomw = input.nextInt();

        if (feedorcomw == 1) {
            String name;
            System.out.print("> Enter your name (first and last): ");
            name = input.nextLine();
            System.out.println("");
            System.out.print("> Enter your mobile (##-###-####): ");
            int num = input.nextInt();

        }

    }
}

Answer 1

您正在提醒这样一个事实，即Scanner#nextLine方法不会使用输入的最后一个换行符，因此在下次调用Scanner#nextLine时会使用该换行符

尝试在那之后添加一个input.nextLine();，一切都会正常工作

例如：

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    System.out.print("    FEEDBACK/COMPLAINT    \n"
            + "                  -\n"
            + "| 1: Submit Feedback |\n"
            + "| 2: Submit Complaint |\n"
            + "| 3: Previous Menu |\n"
            + "                 -\n"
            + "> Please enter the choice: ");
    int feedorcomw = input.nextInt();

    input.nextLine();
    if (feedorcomw == 1) {
        String name;
        System.out.print("> Enter your name (first and last): ");
        name = input.nextLine();
        System.out.println("");
        System.out.print("> Enter your mobile (##-###-####): ");
        int num = input.nextInt();

    }

}