有 Java 编程相关的问题?

你可以在下面搜索框中键入要查询的问题!

java ORA02289:序列不存在,但数据库中不存在序列

我一直在从事一个JavaSpring项目,在这个项目中,我创建了一个类,其唯一目的是记录数据库中调用的每个服务的请求体

该表包含名为transaction_id的主键和记录请求所需的其他字段。Java中的表模型如下所示:

@Entity
@Table(name="ForntEndLogHistory")
public class FrontEndLog {
    
    @Id
    @Column(name = "TRANSACTION_ID")
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_generator")
    @SequenceGenerator(name="id_generator", sequenceName = "id_seq2", allocationSize=1)
    private Long transactionId;
    private String request;
}

在数据库中,我创建了一个名为id_seq2的序列,而id_seq1已经存在:

新创建的id_seq2:

CREATE SEQUENCE  "id_seq2"  MINVALUE 0 MAXVALUE 9999999999999999999999999999 INCREMENT BY 1 START WITH 1 CACHE 20 NOORDER  NOCYCLE ;
commit;

已经存在id_seq1 dll:

CREATE SEQUENCE  "id_seq1"  MINVALUE 0 MAXVALUE 9999999999999999999999999999 INCREMENT BY 1 START WITH 3467 NOCACHE  NOORDER  NOCYCLE ;

案例1:

每当我触发邮递员的任何服务时,序列名为id_seq2的序列生成器就会出现错误“序列不存在”。然而,序列已经存在于DB中

@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_generator")
    @SequenceGenerator(name="id_generator", sequenceName = "id_seq2", allocationSize=1)
    private Long transactionId;

project war文件已成功部署到服务器上。之后,每当邮递员触发服务时,就会发生以下错误:

org.hibernate.exception.SQLGrammarException: could not extract ResultSet
    at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:109)
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:88)
    at org.hibernate.id.SequenceGenerator.generateHolder(SequenceGenerator.java:122)
    at org.hibernate.id.SequenceHiLoGenerator.generate(SequenceHiLoGenerator.java:73)
    at org.hibernate.event.internal.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:117)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:206)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:191)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.performSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:114)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90)
    at org.hibernate.internal.SessionImpl.fireSaveOrUpdate(SessionImpl.java:654)
    at org.hibernate.internal.SessionImpl.saveOrUpdate(SessionImpl.java:646)
    at org.hibernate.internal.SessionImpl.saveOrUpdate(SessionImpl.java:642)
    at com.etisalat.mwallet.data.BaseDAO.save(BaseDAO.java:49)
    at com.etisalat.mwallet.service.impl.LoggerService.logFrontEnd(LoggerService.java:59)
    at com.etisalat.mwallet.service.impl.LoggerService.logFrontEndSuccess(LoggerService.java:29)
    at com.etisalat.mwallet.rest.config.ResponseFilter.doFilter(ResponseFilter.java:180)
    at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:79)
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.wrapRun(WebAppServletContext.java:3436)
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3402)
    at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)
    at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120)
    at weblogic.servlet.provider.WlsSubjectHandle.run(WlsSubjectHandle.java:57)
    at weblogic.servlet.internal.WebAppServletContext.doSecuredExecute(WebAppServletContext.java:2285)
    at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2201)
    at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2179)
    at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1572)
    at weblogic.servlet.provider.ContainerSupportProviderImpl$WlsRequestExecutor.run(ContainerSupportProviderImpl.java:255)
    at weblogic.work.ExecuteThread.execute(ExecuteThread.java:311)
    at weblogic.work.ExecuteThread.run(ExecuteThread.java:263)
Caused by: java.sql.SQLSyntaxErrorException: ORA-02289: sequence does not exist

    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:450)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399)
    at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:1059)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:522)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:257)
    at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:587)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:225)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:53)
    at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:774)
    at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:925)
    at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1111)
    at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:4798)
    at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:4845)
    at oracle.jdbc.driver.OraclePreparedStatementWrapper.executeQuery(OraclePreparedStatementWrapper.java:1501)
    at weblogic.jdbc.wrapper.PreparedStatement.executeQuery(PreparedStatement.java:141)
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:79)

案例2:

之后为了测试,我将序列名从id_seq2更改为id_seq1,并在服务器上重新部署了代码,令人惊讶的是,我能够成功地触发服务

@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_generator")
    @SequenceGenerator(name="id_generator", sequenceName = "id_seq1", allocationSize=1)
    private Long transactionId;

输出:

{

"responseCode": "0"

}

我不知道我在哪里犯了错误,因为在我看来,在序列生成器中我遗漏了一些东西


共 (2) 个答案

  1. # 1 楼答案

    缺失的序列存在可能由两个原因造成:

    1)序列存在于与您连接的不同模式中

    在这种情况下,您必须引用schema_ownerschema_name

    2)序列存在于不同的模式中,您没有访问它的权限

    您应该首先了解现有的序列是在哪个模式中创建的

    您可以通过以下查询进行验证(根据需要替换序列名称)

    select OWNER, OBJECT_NAME SEQUENCE_NAME
    from all_objects where object_type = 'SEQUENCE' 
    and lower(object_name) = 'id_seq1';
    

    如果什么也看不到,那么序列要么不存在,要么存在于与之连接的另一个模式中,并且您对它没有SELECT权限

    如果使用的序列来自与Hibernate连接用户不同的模式(这是一种常见的情况),则必须使用@SequenceGenerator注释的^{}参数,并传递propper模式所有者

  2. # 2 楼答案

    在您的情况下,序列必须与您登录的架构/用户位于同一架构中。如果您以其他用户的身份登录,那么您可以尝试这种相当粗鲁的解决方案

    create public synonym "id_seq2" for "id_seq2";
    grant select on "id_seq2" to public;
    

    或者尝试找出“id_seq1”中的priv和同义词,并将其应用于“id_seq2”