包含多种数据类型的java文件，放入数组，然后对一个数组进行排序，同时将记录保存在一起

Question

我的问题是，我将提供一个包含学生信息的文件：姓名、年龄和GPA。然后我必须将每个数据元素转换成一个单独的数组。然后我必须将GPA按降序排序，同时将姓名和年龄与相应的GPA保持一致，然后用“姓名年龄GPA”标题打印出来

Answer 1

检查下面的代码，根据GPA对数据进行排序。但是，您必须包含文件读取的相关代码

学生。爪哇（POJO）

public class Student {    
    String name;
    int age;
    double GPA;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public int getAge() {
        return age;
    }
    public void setAge(int age) {
        this.age = age;
    }
    public double getGPA() {
        return GPA;
    }
    public void setGPA(double gPA) {
        GPA = gPA;
    }
    public Student(String name, int age, double gPA) {
        super();
        this.name = name;
        this.age = age;
        GPA = gPA;
    }
    @Override
    public String toString() {
        return "Student [name=" + name + ", age=" + age + ", GPA=" + GPA + "]";
    }

}

学生分拣机。java

 import java.util.Comparator;
    public class StudentSorter implements Comparator<Student> {
    @Override
    public int compare(Student o1, Student o2) {        
        if(o1.getGPA() < o2.getGPA()) return 1;
        if(o1.getGPA() > o2.getGPA()) return -1;
        else return 0;
    }   
}

测试仪。java

    public class Tester {
    public static void main(String[] args) {
    Student s1 = new Student("A",14,7.9);
        Student s2 = new Student("B",17,8.2);
        Student s3 = new Student("C",20,7.0);
        Student s4 = new Student("D",15,6.9);
        Student s5 = new Student("E",14,9.1);

        List<Student> list = new ArrayList<>();
        list.add(s1);
        list.add(s2);
        list.add(s3);
        list.add(s4);
        list.add(s5);

        StudentSorter ss = new StudentSorter();
        Collections.sort(list, ss);
        System.out.println(list.toString());        
    }
}