java获取对话框以显示一次
我的应用程序中有一个警报对话框,应用程序一启动就立即启动。我希望我的alertDialog
只在活动安装后首次启动时显示,之后我不希望alertDialog
再次弹出,除非用户删除应用程序,然后再次安装。我试着寻找如何实现这种方法,并尝试学习编写正确的代码,但我似乎无法正确完成。有人能帮我实现这个方法,绕过这个问题吗
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this);
boolean initialDialogDisplayed = preferences.getBoolean("InitialDialog", false);
if (!initialDialogDisplayed) {
Editor editor = preferences.edit();
editor.putBoolean("InitialDialog", true);
editor.commit();
final AlertDialog.Builder alertDialog = new AlertDialog.Builder(this);
alertDialog.setTitle("Alert");
alertDialog.setIcon(R.drawable.ic_launcher);
alertDialog.setMessage("Dialog");
alertDialog.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
}
});
alertDialog.show();
final EditText et = (EditText) findViewById(R.id.editText1);
Button getAnswer = (Button) findViewById(R.id.button1);
getAnswer.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if (et.getText().toString().length()==0) {
Toast.makeText(getApplicationContext(),"Can't Be Blank!",Toast.LENGTH_LONG).show();
}else{
EditText et = (EditText) findViewById(R.id.editText1);
String searchTerm = et.getText().toString().trim();
Intent in = new Intent(MainActivity.this, ListView.class);
in.putExtra("TAG_SEARCH", searchTerm);
startActivity(in);
}
}
});
}
}
@Override
protected void onStop() {
// TODO Auto-generated method stub
super.onStop();
}}
# 1 楼答案
您可以使用共享首选项来存储对话框已经显示的事实。您应该在对话框的显示屏上保存一个值,并读取它以检查是否需要再次显示
# 2 楼答案
可以通过SharedReferences存储标志值
链接:http://developer.android.com/guide/topics/data/data-storage.html#pref