java如何将jodatime与jaxb绑定

Question

我要上这样的课

@XmlRootElement(name = "executionStats")
public class ScriptExecutionStatistics {

private DateTime start;
private DateTime end;

public ScriptExecutionStatistics() { }

public ScriptExecutionStatistics(DateTime start, DateTime end) {
    this.start = start;
    this.end = end;
}

@XmlAttribute
public DateTime getStart() {
    return start;
}

public void setStart(DateTime start) {
    this.start = start;
}

@XmlAttribute
public DateTime getEnd() {
    return end;
}

public void setEnd(DateTime end) {
    this.end = end;
}

}

我想用xml对它进行序列化，所以看起来像这样

<scriptExecutionStatistics start="17.08.2015 18:17:00" end="17.08.2015 18:18:00" />

我知道，如果我想将joda time与jaxb绑定，就需要一个适配器，但令人困惑的是，我并没有真正理解它。所以我从

public class DateTimeAdapter extends XmlAdapter<ScriptExecutionStatistics, DateTime>{
private static DateTimeFormatter dtf = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");

@Override
public DateTime unmarshal(ScriptExecutionStatistics vt) throws Exception {
    throw new UnsupportedOperationException("Not supported yet.");
}

@Override
public ScriptExecutionStatistics marshal(DateTime bt) throws Exception {
    ScriptExecutionStatistics stats = new ScriptExecutionStatistics();

}

}

你能帮我把它做完吗。 提前谢谢

Answer 1

DateTimeAdapter应该封送/取消封送DateTime到String例如

public class DateTimeAdapter extends XmlAdapter<String, DateTime>{
   private static DateTimeFormatter dtf = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");

   @Override
   public DateTime unmarshal(String vt) throws Exception {
       return dtf.parseDateTime(vt);
   }

   @Override
   public String marshal(DateTime bt) throws Exception {
       return dtf.print(bt);

   }
}

此外，您还应该使用@XmlJavaTypeAdapter注释ScriptExecutionStatistics中适当的字段/getter

@XmlJavaTypeAdapter(DateTimeAdapter.class)
@XmlAttribute
public DateTime getStart() {
    return start;
}