java代码在试图查找同时为星形和三角形的数字时不打印

Question

我正在尝试为一个程序编写代码，该程序可以打印星号和三角形的值。虽然代码似乎不起作用，也不会打印出任何值，但星号的函数运行良好，尽管我认为三角形数的函数有点不确定，但我不确定问题出在哪里

我们将不胜感激 谢谢

public class TriangularNumbers {

    public static void main(String[] args) {
        int n = 1;
        int i = 1;
        int star = starNumbers(n);
        int triangle = triangleNumbers(i, n);

        while (star > 0)
        {   
            while (star < triangle)
            {
                n++;
                star = starNumbers(n);
            }
            while (triangle < star)
            {
                triangle = triangleNumbers(i, n);
            }
            if (star==triangle)
            {
                System.out.println(star);
            }
        }
    }
    private static int starNumbers (int n) {
        int s = ((6*n)*(n-1)+1);
        return s;
    }
    private static int triangleNumbers( int i, int n){
        int star = starNumbers(n);
        int t = 0;
        while (t<=star)
        {
            t = t + i;
            i++;
        }
        return t;
    }
}

Answer 1

//try this

public class TriangularNumbers {

    public static void main(String[] args) {
        int n = 1;
        int i = 1;
        int star = starNumbers(n);
        int triangle = 0;

        while (star > 0){
            star = starNumbers(n++);
            triangle=0;
            //System.out.println("Star "+star);
            while(triangle < star){

                triangle = triangleNumbers(i,star);

                if(star == triangle){
                    System.out.println("match at "+star);
                }
            }
        }
    }

    private static int starNumbers (int n) {
        int s = ((6*n)*(n-1)+1);
        return s;
    }

    private static int triangleNumbers( int i, int star){
        int t = 0;
        while (t<star){
            t = i*(i+1)/2; //get next triangle
            i++;
        }
        return t;
    }
}