java如何读取文件中的双值

Question

我有一个这样的文件

07/15/14: 19.33

07/15/14: 13.14

07/15/14: 21.20

07/15/14: 22.67

我需要一种方法来读取这些双值并打印出平均值。这就是数字的保存方式

public void hourlyOverall() throws IOException
{
    //construct the date to print into a file
    java.sql.Date date=new java.sql.Date(time);
    //set hourlyOverall variable
    hourlyOverall=tips/hours+hourlyWage;
    //construct the printwriter with a file writer in it.  
    //set the FileWriter append parameter too true so that the 
    //info is added onto the end of the file, and the file is
    //not overwritten
    PrintWriter editFile=new PrintWriter(new FileWriter("wage info",true));
    editFile.printf("%tD: %.2f \n ", date, hourlyOverall);
    editFile.close();
}

这就是我试图阅读它们的方式

public double totalHourlyOverall() throws FileNotFoundException
{
    Scanner fileScanner=new Scanner(fos);
    while(fileScanner.hasNextDouble())
    {
            total+=fileScanner.nextDouble();
            counter+=1;
    }
    fileScanner.close();
    return overallHourly=total/counter;
}

但它并没有拿到双打。我做错了什么

编辑：

所以我现在得到一个数组越界异常。我的代码是这样的

public double totalHourlyOverall() throws FileNotFoundException

{
    Scanner fileScanner=new Scanner(fos);
    while(fileScanner.hasNextLine())
    {
            String str=fileScanner.nextLine();
            String[] array=str.split(":");
            total+=Double.parseDouble(array[1]);
            counter+=1;
    }
    fileScanner.close();
    return overallHourly=total/counter;
}

应该有一个数组[1]，因为每一行被分成两行，对吗

Answer 1

我觉得你应该一行一行地读，然后跳过10个字符，一直读到最后

Answer 2

另一种方法是使用Pattern和Matcher

Pattern p = Pattern.compile("(\\b[-\\d\\.]+\\b)");   // pattern to match any double value (+/-) with boundaries
Matcher m;
while(fileScanner.hasNextLine()) {
    String line = fileScanner.nextLine();
    m = p.matcher(line); // try to match the regular expression
    if ( m.find() ) {
        String value = m.group(1); // get the match in group 1
        // turn to a double, etc...
    }
}