java忽略空格，只计算字母

Question

你能给我们的程序一个想法，忽略空格，只计算字母表，甚至是小的其他明智的上限吗

public class evennumbersloop {

    public static void main(String[] args) {

        String str = "Hello World uuuu iii pppp jjj";

        int count = 0;

        for (int i = 0; i <= str.length() - 1; i++) {

            if (str.charAt(i) != ' ') {
                if (count % 2 == 0) {
                    String str1 = "";
                    str1 = str1 + str.charAt(count);
                    System.out.print(str1.toUpperCase());
                } else {
                    System.out.print(str.charAt(count));
                }

                count++;
            }
        }

    }
}

Answer 1

你是说

String str = "Hello World uuuu iii pppp jjj";

忽略空白并计算出现的字母数>；实际上是没有空格的字符串长度

String str = "Hello World uuuu iii pppp jjj";
System.out.println("Length of string with spaces: "+str.length());
str = str.replaceAll("\\s", "");
System.out.println("Length of String without white spaces: "+str.length());

输出：

Length of string with spaces: 29
Length of String without white spaces: 24