Java:读取包含许多嵌套元素的xml
我有一个看起来有点类似于以下内容的xml。我需要从属性和标记中获取值并存储它们。但我不明白如何进入2级(3、4等)嵌套元素。我使用了我在互联网上找到的以下代码,它使用了DOM,但我无法获得正确的RegNumber及其属性。提前谢谢
nodeList = xmldocument.getElementsByTagName("Header"); if (nodeList != null && nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //get the header element Element header = (Element) nodeList.item(i); System.out.println("Element: " + ((Element)nodeList.item(i)).getNodeName()); System.out.println(header.getAttribute("time")); } } nodeList = xmldocument.getElementsByTagName("Document"); if (nodeList != null && nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //get the document element Element document = (Element) nodeList.item(i); System.out.println("Element: " + ((Element)nodeList.item(i)).getNodeName()); System.out.println(document.getAttribute("Id")); nodeList = document.getElementsByTagName("RegNumber"); for (int j = 0; j < nodeList.getLength(); j++) { //get the RegNumber element Element regNumber = (Element) nodeList.item(j); System.out.println("Element: " + ((Element)nodeList.item(j)).getNodeName()); System.out.println(regNumber.getAttribute("regpoint")); } } }
xml:
<XML xsi:schemaLocation="http://www.codetools.it XSD2.xsd" xmlns="http://www.codetools.it" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Header time="2001-12-17T09:30:47Z" />
<Document Id="456">
<RegNumber regpoint="" regdate="2001-12-17T09:30:47Z">123/456</RegNumber>
<Confident flag="0"/>
<DocNumber kind="">
<RegNumber RegPoint="" regdate="2001-12-17T09:30:47Z">456/789</RegNumber>
<Organization fullname="lol" shortname="" ownership="lol" ogrn="78945612" inn="">
<OfficialPerson>
<Name Firstname="John"/>
<Official Department="" post=""/>
<SignDate>2001-12-17T09:30:47Z</SignDate>
</OfficialPerson>
<Econtact type="1">test@test.com.ua</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</DocNumber>
<DocTransfer os="Windows" type=".docx" type_ver="" char_set="" description="kkkk">
</DocTransfer>
<Reghistory idnumber="">
<RegNumber RegPoint="" regdate=""/>
<Organization fullname="" shortname="" ownership="" ogrn="" inn="">
<Econtact type=""/>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</Reghistory>
<Author>
<Organization fullname="" shortname="" ownership="" ogrn="12345678" inn="">
<OfficialPerson>
<Name Firstname="" />
<Official Department="" post=""/>
<SignDate>2011-12-17T09:30:47Z</SignDate>
</OfficialPerson>
<Econtact type="Рї">smirnov@test.com</Econtact>
<Address street="" postcode="1234" postbox="" flat="" district="" region="" country="" nontypical="" house="12"/>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""/>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<SignDate/>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Author>
<Validator attestation="0">
<DocNumber kind="наказ">
<RegNumber RegPoint="" regdate="2001-12-17T09:30:47Z"/>
<Organization fullname="" shortname="" ownership="" ogrn="14725836" inn="">
<Econtact type="Рї">kmu@test.com</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</DocNumber>
<Organization fullname="" shortname="РљРњРЈ" ownership="" ogrn="96325878" inn="">
<Econtact type="String">kmu@test.com</Econtact>
<Address street="Пушкіна" settlement="" postcode="4563" postbox="" flat="" district="" region="" country="" nontypical="" house="23"/>
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Official Department="" post=""/>
<SignDate>2011-12-17T09:30:47Z</SignDate>
</OfficialPerson>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<SignDate></SignDate>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Validator>
<Addressee>
<Referred id="" retype="">
<RegNumber regdate="" regpoint=""/>
<TaskNumber taskDate=""/>
</Referred>
<Organization fullname="String" shortname="" ownership="" ogrn="85236974" inn="">
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Official Department="" post=""/>
</OfficialPerson>
<Econtact type="Рї">sofki@test.com</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" type="" house=""/>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Addressee>
<Writer>
<Organization fullname="" shortname="" ownership="" ogrn="" inn="">
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
</OfficialPerson>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
</PrivatePerson>
</Writer>
</Document>
编辑。按照建议,我试图找出JAXB的东西。xjc工具生成了3个类:ObjectFactory、package info和XML。我发现以下代码用于从xml创建对象:
public static void main(String[] args) {
try {
File file = new File("F:\\Untitled3.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(XML.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
XML xml = (XML) jaxbUnmarshaller.unmarshal(file);
System.out.println(xml);
} catch (JAXBException e) {
e.printStackTrace();
}
}
这是正确的方法,还是我需要使用ObjectFactory
ObjectFactory f =new ObjectFactory();
XML xml1 = f.createXML();
如何创建包含所有标记和属性的对象,然后从中创建xml文件?我对java和jaxb还不熟悉,所以请耐心听我说
# 1 楼答案
在每个节点上再次使用“getElementsByTagName”函数,以按标记名获取元素。显然
下面是我的示例代码,深入到几个层次:
# 2 楼答案
对于允许您在特定深度访问节点的方法,它通常没有意义或通常没有用处。这不仅仅是关于Java,而是关于DOM规范,我相信这是正确的决定
人们通常通过多种有意义的方式之一访问节点:
查找xpath,这将非常有用